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alfers101

  • 2 years ago

Please help: Calculate the electric field at the center of a square 52.5cm on a side if one corner is occupied by a +45uC charge and the other three occupied by -27uC charges.

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  1. ujjwal
    • 2 years ago
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    Find electric field due to individual charges at the center and do their vector sum. That will give you the resultant field. P.S. you mustn't make any mistake while determining the direction of electric field due to individual charges.|dw:1340434465357:dw|

  2. alfers101
    • 2 years ago
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    uhm okay. i think thats it.

  3. ujjwal
    • 2 years ago
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    |dw:1340434775644:dw|The electric fields due to charges at B and D seems to cancel each other. So, you have got only A and C.

  4. alfers101
    • 2 years ago
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    okay then?

  5. ujjwal
    • 2 years ago
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    calculate the fields due to individual charges and do the vector sum.

  6. salini
    • 2 years ago
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    break the problem into parts: force(here electric field) always acts through the line joining the charges so it is enough if u consider forces along AC and BD imagine placing a positive test charge(with no electric field of its own at the centre. along BD , since u have two equal charges attracting a test charge(+ve) equally the effect due to them is zero same way think wat should happen along AC then use formulae q/(4 pi epsilonnt r^@) |dw:1340437859485:dw| u can see that we are taking only charge q in the eqn as electric field is nothing but force/unit charge first u have to draw a diagram like ujjwal for clarity

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