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luisz

  • 2 years ago

Farial inscribed a quadrilateral ABCD in a circle, as shown below. If the measure of arc BCD is 220°, what is the measure of angle BCD?

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  1. luisz
    • 2 years ago
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  2. luisz
    • 2 years ago
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    yeh!!!

  3. luisz
    • 2 years ago
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    any tips?

  4. LoveYou*69
    • 2 years ago
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    I don't know:( I am sorry, I will try to get someone who will know here tho!:D

  5. luisz
    • 2 years ago
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    ty

  6. luisz
    • 2 years ago
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    k

  7. luisz
    • 2 years ago
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    so did you get someone?

  8. luisz
    • 2 years ago
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    ty

  9. terenzreignz
    • 2 years ago
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    Are you sure it's the measure of angle BCD you want? you just gave its measure...

  10. luisz
    • 2 years ago
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    yes, we need the measure of angle BCD...

  11. luisz
    • 2 years ago
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    I mean arc!!!!!!!!!!!!!!!!

  12. luisz
    • 2 years ago
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    sorry

  13. luisz
    • 2 years ago
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    no

  14. luisz
    • 2 years ago
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    I mean angle

  15. luisz
    • 2 years ago
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    sorry

  16. legoauto220
    • 2 years ago
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    |dw:1340465784240:dw| Like this? IS the image correct? And we have to get the angle now, the angle C

  17. luisz
    • 2 years ago
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    Yes, angle BCD

  18. THE_PROPHET
    • 2 years ago
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    70

  19. luisz
    • 2 years ago
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    can you tell me how?

  20. luisz
    • 2 years ago
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    why is at 70?

  21. luisz
    • 2 years ago
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    its correct but why?

  22. legoauto220
    • 2 years ago
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    Because 360-220=140, and the central angle is double the angle in the circumfrence, so its 70

  23. luisz
    • 2 years ago
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    ty

  24. luisz
    • 2 years ago
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    I thought the same exact thing

  25. legoauto220
    • 2 years ago
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    |dw:1340466383693:dw|

  26. luisz
    • 2 years ago
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    I wasn't sure if it was correct, though.

  27. luisz
    • 2 years ago
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    ty

  28. legoauto220
    • 2 years ago
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    np

  29. THE_PROPHET
    • 2 years ago
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    angle BOD =140 centre is O angle subtended by chord on cente is twice the angle subtended on the circle .....so 2x = 140 x = 70

  30. luisz
    • 2 years ago
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    let me post another problem...

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