Gina wrote the following paragraph to prove that the segment joining the midpoints of two sides of a triangle is parallel to the third side.
Given: ∆ABC
Prove: The midsegment between sides Line segment AB and Line segment BC is parallel to side Line segment AC.
Draw ∆ABC on the coordinate plane with point A at the origin (0, 0). Let point B have the ordered pair (x1, y1) and locate point C on the x-axis at (x2, 0). Label point D as the midpoint of Line segment AB with coordinates at Ordered pair the quantity 0 plus x sub 1, divided by 2; the quantity 0 plus y sub 1, divided by 2 by th

- anonymous

- chestercat

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- anonymous

eh

- anonymous

hold on

- anonymous

Gina wrote the following paragraph to prove that the segment joining the midpoints of two sides of a triangle is parallel to the third side.
Given: ∆ABC
Prove: The midsegment between sides Line segment AB and Line segment BC is parallel to side Line segment AC.
Draw ∆ABC on the coordinate plane with point A at the origin (0, 0). Let point B have the ordered pair (x1, y1) and locate point C on the x-axis at (x2, 0). Label point D as the midpoint of Line segment AB with coordinates at Ordered pair the quantity 0 plus x sub 1, divided by 2; the quantity 0 plus y sub 1, divided by 2 by the Midpoint Formula. Label point E so it is the midpoint of Line segment BC with an ordered pair of Ordered pair the quantity of x sub 1 plus x sub 2 divided by 2; the quantity of 0 plus y sub 1 divided by 2 by the Midpoint Formula. The slope of Line segment DE is found to be 0 through the application of the slope formula: The difference of y sub 2 and y sub 1, divided by the difference of x sub 2 and x sub 1 is equal to the difference of the quantity 0 plus y sub 1, divided by 2, and the quantity 0 plus y sub 1, divided by 2, divided by the difference of the quantity x sub 1 plus x sub 2, divided by 2 and the quantity 0 plus x sub 1, divided by 2 is equal to 0 divided by the quantity x sub 2 divided by 2 is equal to 0 When the slope formula is applied to Line segment AC the difference between y sub 2 and y sub 1, divided by the difference of x sub 2 and x sub 1 is equal to the difference of 0 and 0, divided by the difference of x sub 2 and 0 is equal to 0 divided by x sub 2 is equal to 0, its slope is also 0. Since the slope of Line segment DE and Line segment AC are identical, Line segment DE and Line segment AC are parallel by the definition of parallel lines.

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## More answers

- anonymous

does that help at all?

- anonymous

http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/1001/1001_G4_Q12b.gif

- anonymous

hold up

- anonymous

##### 1 Attachment

- anonymous

##### 1 Attachment

- anonymous

##### 1 Attachment

- anonymous

##### 1 Attachment

- anonymous

helps any?

- anonymous

you guys there?

- anonymous

oh....

- anonymous

forgot

- anonymous

here are the answer choices...

- anonymous

What is the flaw in Gina’s proof?
Points D and E must be constructed, not simply labeled, as midpoints.
Segments DE and AC are parallel by construction.
The slope of segments DE and AC is not 0.
The coordinates of D and E were found using the Distance between Two Points Postulate

- KingGeorge

Is it this question? http://assets.openstudy.com/updates/attachments/4fe3df92e4b06e92b872936f-yourmom14-1340333980899-georgeiiieiehjkdhkjs.jpg

- anonymous

where did you find that?

- KingGeorge

It was a question I answered two days ago.

- anonymous

Did you find it on FLVS online?

- anonymous

I am a Florida Virtual School Student

- anonymous

so

- anonymous

can you help me out here?

- KingGeorge

First off, which choices can we easily eliminate?

- anonymous

Choice three is erroneous

- anonymous

AC is 0

- KingGeorge

Right, any others you can see are obviously wrong?

- anonymous

and the distance formula was never used, so we can eliminate 4

- anonymous

But there was a flaw in her work

- anonymous

I have a feeling that her flaw was in choice 1

- KingGeorge

Right again. Now it's up to 1 or 2. Let's look at 1.
Did Gina construct D and E, or did she label them?

- anonymous

Points D and E must be constructed, not simply labeled, as midpoints.

- anonymous

hmm

- anonymous

She only labeled them

- anonymous

she did not construct them

- KingGeorge

Right. So the flaw is that she labeled them

- anonymous

k

- anonymous

by browser logged off automatically without my permission :(

- anonymous

i lost my answers

- anonymous

hold on

- anonymous

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- anonymous

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- anonymous

:D!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

- anonymous

I didn't lose them!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

- anonymous

k!!!!!!!!!!!!!!!!

- anonymous

two more nasty suckers coming up

- anonymous

wats was the answer to this problem,

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