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Try pluging all values till 6 and -6, it doenst look like this function have rational zeros.
All possible rational zeros: p/q where p is the constant and q is the leading coefficient. ±1/4, ±1/2, ±3/4, ±1, ±3/2, ±2, ±3, ±6.
From wolf. http://www.wolframalpha.com/input/?i=0+%3D+4x%5E3+%E2%80%93+5x%5E2+%2B+9x+%E2%80%93+6.+
±2/4 and ±6/4 are already there, but simplified.
can you explain to me what your tallking about please
Alright, Do you know the rational root theorem though? How you got the ±1, ±2, etc?
First I found the factors of -6 and 4
Yeah. THat's called the rational root theorem. Your answer is generally correct, but all I was saying was that 6/4 = 3/2 and 2/4 = 1/2 which are already there. Those additional ones like I said are unnecessary.
So, your answer is correct :)
okay just write out the final answer for me to make sure
±1/4, ±1/2, ±3/4, ±1, ±3/2, ±2, ±3, ±6