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sara1234

  • 2 years ago

find all possible rational zeros of the polynomial function f(x) = 4x^3 – 5x^2 + 9x – 6. I did it and I got +-1 +-2+- 3+- 6 +-1/2 +- 3/2 +- 1/4+- 2/4+- 3/4+- 6/4 can some one please check my work thanks

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  1. truck
    • 2 years ago
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    hold up

  2. truck
    • 2 years ago
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    Try pluging all values till 6 and -6, it doenst look like this function have rational zeros.

  3. Calcmathlete
    • 2 years ago
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    All possible rational zeros: p/q where p is the constant and q is the leading coefficient. ±1/4, ±1/2, ±3/4, ±1, ±3/2, ±2, ±3, ±6.

  4. RolyPoly
    • 2 years ago
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    From wolf. http://www.wolframalpha.com/input/?i=0+%3D+4x%5E3+%E2%80%93+5x%5E2+%2B+9x+%E2%80%93+6.+

  5. Calcmathlete
    • 2 years ago
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    ±2/4 and ±6/4 are already there, but simplified.

  6. sara1234
    • 2 years ago
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    can you explain to me what your tallking about please

  7. Calcmathlete
    • 2 years ago
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    Alright, Do you know the rational root theorem though? How you got the ±1, ±2, etc?

  8. sara1234
    • 2 years ago
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    First I found the factors of -6 and 4

  9. Calcmathlete
    • 2 years ago
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    Yeah. THat's called the rational root theorem. Your answer is generally correct, but all I was saying was that 6/4 = 3/2 and 2/4 = 1/2 which are already there. Those additional ones like I said are unnecessary.

  10. Calcmathlete
    • 2 years ago
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    So, your answer is correct :)

  11. sara1234
    • 2 years ago
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    okay just write out the final answer for me to make sure

  12. Calcmathlete
    • 2 years ago
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    ±1/4, ±1/2, ±3/4, ±1, ±3/2, ±2, ±3, ±6

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