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I don't understand what it's asking for is it asking to find positive negitive and complex?

huh? for no of?

Yeah, Using Descartes' Rule of Signs we can determine that. I'll explain you

isnt there 5 sign changes?

oh never miind i got it

yes

Now can you write f(-x), it's used to find no. of negative zeros

-3(-x)^5-8(-x)^4+25^3-8(-x)^2+(-x)-19

Yes i do

Now count the no. of sign changes here

only one

Yeah thankssss!! Now we find complex?

why do we have to add the ) positive?

Because 0 could be due to 4 complex roots

theres 4 or 2 positive real zeros but why do we have to add the 0

There could be a double quadratic, with 4 roots complex. therefore we won't have any positive zero

you're welcome. did you understand all the things?

Yessss :D