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What are the possible rational zeros of f(x) = 3x^4 + x^3 – 13x^2 – 2x + 9? ± 1, ± 3 ± 1, ± 3, ± 9 ± 1, ± , ± , ± 3 ± 1, ± , ± 3, ± 9 i got d am I right

Mathematics
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if f(x)= ax^4 + bx^3 + cx^3 +dx + e then possible rational zeros of f(x) according to ration root theorem are : ±(factors of e)/(factors of a) [note e is not exponent but any constatnt] all permutations and combinations of factors can be a root. try now..
rational root theorem **
for d i forgot to put the 1/3

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\( 3x^4 + x^3 – 13x^2 – 2x + 9 \) Using the rational root theorem ( http://en.wikipedia.org/wiki/Rational_root_theorem ) \(\pm\) Factors of 9 / Factors of 3 In this case, \[ \pm \frac {1,3,9}{1,3} \]
okay so my answer was right ± 1, ± 1/3, ± 3, ± 9
thanks guys
Yes that's right :)

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