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What will be the remainder after we divide 50! + 49! + 48!.......2! + 1! by 5! ?
 one year ago
 one year ago
How will we solve this? What will be the remainder after we divide 50! + 49! + 48!.......2! + 1! by 5! ?
 one year ago
 one year ago

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ParthKohliBest ResponseYou've already chosen the best response.0
@FoolForMath I need your genius here
 one year ago

ash2326Best ResponseYou've already chosen the best response.4
50!.... 5! each of these have a 5! so remainder will be 4!+3!+2!+1!=24+6+2+1=33
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
I am not sure how you got it :
 one year ago

FoolForMathBest ResponseYou've already chosen the best response.1
It's easy, Starting from 5! every factorial is a divisible by 5.
 one year ago

FoolForMathBest ResponseYou've already chosen the best response.1
So, just ignore the rest.
 one year ago

ash2326Best ResponseYou've already chosen the best response.4
Did you understand @ParthKohli ?
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
Yes! that's the principle of how we divide \(\Large {6! \over 5!}\) and we get \(6\)... so 6 is the quotient and there is no remainder! ^.^
 one year ago

mukushlaBest ResponseYou've already chosen the best response.0
how about equation 1!+2!+3!+...+n!=n^2 how many answers does it have n is nature?
 one year ago
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