ParthKohli
How will we solve this?
What will be the remainder after we divide 50! + 49! + 48!.......2! + 1! by 5! ?



This Question is Closed

ParthKohli
Best Response
You've already chosen the best response.
0
@FoolForMath I need your genius here

ash2326
Best Response
You've already chosen the best response.
4
50!.... 5! each of these have a 5!
so remainder will be 4!+3!+2!+1!=24+6+2+1=33

ParthKohli
Best Response
You've already chosen the best response.
0
I am not sure how you got it :

FoolForMath
Best Response
You've already chosen the best response.
1
It's easy, Starting from 5! every factorial is a divisible by 5.

FoolForMath
Best Response
You've already chosen the best response.
1
So, just ignore the rest.

ParthKohli
Best Response
You've already chosen the best response.
0
Oh yes!

ash2326
Best Response
You've already chosen the best response.
4
Did you understand @ParthKohli ?

ParthKohli
Best Response
You've already chosen the best response.
0
Yes! that's the principle of how we divide \(\Large {6! \over 5!}\) and we get \(6\)... so 6 is the quotient and there is no remainder! ^.^

ademm37
Best Response
You've already chosen the best response.
0
dw:1340545398596:dw

mukushla
Best Response
You've already chosen the best response.
0
how about equation 1!+2!+3!+...+n!=n^2 how many answers does it have n is nature?

ParthKohli
Best Response
You've already chosen the best response.
0
Thank you all!