## ParthKohli 2 years ago How will we solve this? What will be the remainder after we divide 50! + 49! + 48!.......2! + 1! by 5! ?

1. ParthKohli

@FoolForMath I need your genius here

2. ash2326

50!.... 5! each of these have a 5! so remainder will be 4!+3!+2!+1!=24+6+2+1=33

3. ParthKohli

I am not sure how you got it :|

4. FoolForMath

It's easy, Starting from 5! every factorial is a divisible by 5.

5. FoolForMath

So, just ignore the rest.

6. ParthKohli

Oh yes!

7. ash2326

Did you understand @ParthKohli ?

8. ParthKohli

Yes! that's the principle of how we divide $$\Large {6! \over 5!}$$ and we get $$6$$... so 6 is the quotient and there is no remainder! ^.^

|dw:1340545398596:dw|

10. mukushla

how about equation 1!+2!+3!+...+n!=n^2 how many answers does it have n is nature?

11. ParthKohli

Thank you all!