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ParthKohli
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How will we solve this?
What will be the remainder after we divide 50! + 49! + 48!.......2! + 1! by 5! ?
 2 years ago
 2 years ago
ParthKohli Group Title
How will we solve this? What will be the remainder after we divide 50! + 49! + 48!.......2! + 1! by 5! ?
 2 years ago
 2 years ago

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ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
@FoolForMath I need your genius here
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.4
50!.... 5! each of these have a 5! so remainder will be 4!+3!+2!+1!=24+6+2+1=33
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
I am not sure how you got it :
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.1
It's easy, Starting from 5! every factorial is a divisible by 5.
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.1
So, just ignore the rest.
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.4
Did you understand @ParthKohli ?
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
Yes! that's the principle of how we divide \(\Large {6! \over 5!}\) and we get \(6\)... so 6 is the quotient and there is no remainder! ^.^
 2 years ago

ademm37 Group TitleBest ResponseYou've already chosen the best response.0
dw:1340545398596:dw
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.0
how about equation 1!+2!+3!+...+n!=n^2 how many answers does it have n is nature?
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
Thank you all!
 2 years ago
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