anonymous
  • anonymous
What is the surface area of the composite figure? ~Attachment in comments~
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
1 Attachment
Shane_B
  • Shane_B
Take it in pieces and sum up the values at the end. It's going to be:\[SA_{bottom}+4SA_{side}+4SA_{triangle~side}\]
Shane_B
  • Shane_B
If you're stumped on this let me know and I'll walk you through it.

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anonymous
  • anonymous
It would help if you could walk me through it, please?
Shane_B
  • Shane_B
Ok, the bottom of the figure is a square with 6mm sides right? Well, the SA of a square is just side*side: \[6mm*6mm=36mm^2\]
Shane_B
  • Shane_B
The sides are rectangles so it's basically SA = LW:\[7mm*6mm=42mm^2\]
Shane_B
  • Shane_B
The top parts are just triangles with a 6mm base and a height of 4mm. The SA of a triangle is (1/2)bh:\[\frac{(6mm)(4mm)}{2}=12mm^2\]
Shane_B
  • Shane_B
Now use the first equation I posted which sums it all up to get the total surface area. If you work it out I'll double-check your answer.
anonymous
  • anonymous
For some reason I've got 90 mm^2 but that's not even close to one of the answers I have :/
Shane_B
  • Shane_B
I think I lost you...here:\[SA_{total}=SA_{bottom}+4SA_{side}+4SA_{triangle~side}\]\[SA_{total}=36+4(42)+4(12)=?\]
Shane_B
  • Shane_B
There's no magic formula when doing these types of problems. You just take the individual areas and sum them up at the end.
anonymous
  • anonymous
252 mm^2?
Shane_B
  • Shane_B
Yes
anonymous
  • anonymous
Thank you!
Shane_B
  • Shane_B
yw, good luck :)

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