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Ishaan94
 3 years ago
Number of ways the word 'SUCCESS' can be arranged, such that no two S's and C's are together.
@Zarkon
Ishaan94
 3 years ago
Number of ways the word 'SUCCESS' can be arranged, such that no two S's and C's are together. @Zarkon

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siddhantsharan
 3 years ago
Best ResponseYou've already chosen the best response.2Hold on. No. 120  24 = 96?

Ishaan94
 3 years ago
Best ResponseYou've already chosen the best response.1I can't be sure of the answer. To convince me you would need to show working as well.

Ishaan94
 3 years ago
Best ResponseYou've already chosen the best response.1In my textbook 36 is the given answer. But I don't think it's right, now that siddhant and another guy I knew answered 96 instead.

Chumku
 3 years ago
Best ResponseYou've already chosen the best response.0no. of letters= 7 no. of s = 3 no. of c = 2 therfore no. of combination= 7!/2!3!

Ishaan94
 3 years ago
Best ResponseYou've already chosen the best response.1Chumku read the question again.

Ishaan94
 3 years ago
Best ResponseYou've already chosen the best response.1lol :( Byron left me an complicated answer. Integral and stuff.

Ishaan94
 3 years ago
Best ResponseYou've already chosen the best response.1siddhan can you post the solution as well? or, a hint.

siddhantsharan
 3 years ago
Best ResponseYou've already chosen the best response.2Yeahhh. Sorry. Do you want the solution or hint?

siddhantsharan
 3 years ago
Best ResponseYou've already chosen the best response.2Actually since you're not sure, I think I should post my solution. I may be wrong. So, No. of cases with no two C's together and no two S's together = No. of cases with no two S's together ( C's can me arranged anyhow)  No. of cases with no two S's together ( C's being together now)

siddhantsharan
 3 years ago
Best ResponseYou've already chosen the best response.2Does that seem correct so far? @Ishaan94

siddhantsharan
 3 years ago
Best ResponseYou've already chosen the best response.2dw:1340389706521:dw Writing the letters with spaces between them. And only putting S's in the spaces so as to ensure their seperation. Total ways of doing this ( S's together C's anyhow) : 5C2 * 4!/2!

Ishaan94
 3 years ago
Best ResponseYou've already chosen the best response.1And it also proves how simple this problem could be

Ishaan94
 3 years ago
Best ResponseYou've already chosen the best response.1And how stupid I think at times sigh

siddhantsharan
 3 years ago
Best ResponseYou've already chosen the best response.2Yeah. It's pretty simple now.
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