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Number of ways the word 'SUCCESS' can be arranged, such that no two S's and C's are together.
@Zarkon
 one year ago
 one year ago
Number of ways the word 'SUCCESS' can be arranged, such that no two S's and C's are together. @Zarkon
 one year ago
 one year ago

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siddhantsharanBest ResponseYou've already chosen the best response.2
Hold on. No. 120  24 = 96?
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.1
I can't be sure of the answer. To convince me you would need to show working as well.
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.1
In my textbook 36 is the given answer. But I don't think it's right, now that siddhant and another guy I knew answered 96 instead.
 one year ago

ChumkuBest ResponseYou've already chosen the best response.0
no. of letters= 7 no. of s = 3 no. of c = 2 therfore no. of combination= 7!/2!3!
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.1
Chumku read the question again.
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.1
lol :( Byron left me an complicated answer. Integral and stuff.
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.1
siddhan can you post the solution as well? or, a hint.
 one year ago

siddhantsharanBest ResponseYou've already chosen the best response.2
Yeahhh. Sorry. Do you want the solution or hint?
 one year ago

siddhantsharanBest ResponseYou've already chosen the best response.2
Actually since you're not sure, I think I should post my solution. I may be wrong. So, No. of cases with no two C's together and no two S's together = No. of cases with no two S's together ( C's can me arranged anyhow)  No. of cases with no two S's together ( C's being together now)
 one year ago

siddhantsharanBest ResponseYou've already chosen the best response.2
Does that seem correct so far? @Ishaan94
 one year ago

siddhantsharanBest ResponseYou've already chosen the best response.2
dw:1340389706521:dw Writing the letters with spaces between them. And only putting S's in the spaces so as to ensure their seperation. Total ways of doing this ( S's together C's anyhow) : 5C2 * 4!/2!
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.1
And it also proves how simple this problem could be
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.1
And how stupid I think at times sigh
 one year ago

siddhantsharanBest ResponseYou've already chosen the best response.2
Yeah. It's pretty simple now.
 one year ago
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