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Ishaan94 Group Title

Number of ways the word 'SUCCESS' can be arranged, such that no two S's and C's are together. @Zarkon

  • 2 years ago
  • 2 years ago

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  1. Ishaan94 Group Title
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    And @siddhantsharan

    • 2 years ago
  2. Chumku Group Title
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    \[7!/2!3!\]

    • 2 years ago
  3. siddhantsharan Group Title
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    Hold on. No. 120 - 24 = 96?

    • 2 years ago
  4. Ishaan94 Group Title
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    I can't be sure of the answer. To convince me you would need to show working as well.

    • 2 years ago
  5. Ishaan94 Group Title
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    In my textbook 36 is the given answer. But I don't think it's right, now that siddhant and another guy I knew answered 96 instead.

    • 2 years ago
  6. Chumku Group Title
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    no. of letters= 7 no. of s = 3 no. of c = 2 therfore no. of combination= 7!/2!3!

    • 2 years ago
  7. Ishaan94 Group Title
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    Chumku read the question again.

    • 2 years ago
  8. Ishaan94 Group Title
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    know*

    • 2 years ago
  9. Chumku Group Title
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    oh i get it sorry

    • 2 years ago
  10. Ishaan94 Group Title
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    lol :( Byron left me an complicated answer. Integral and stuff.

    • 2 years ago
  11. Ishaan94 Group Title
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    a*

    • 2 years ago
  12. Ishaan94 Group Title
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    siddhan can you post the solution as well? or, a hint.

    • 2 years ago
  13. Ishaan94 Group Title
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    siddhant*

    • 2 years ago
  14. siddhantsharan Group Title
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    Yeahhh. Sorry. Do you want the solution or hint?

    • 2 years ago
  15. siddhantsharan Group Title
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    Actually since you're not sure, I think I should post my solution. I may be wrong. So, No. of cases with no two C's together and no two S's together = No. of cases with no two S's together ( C's can me arranged anyhow) - No. of cases with no two S's together ( C's being together now)

    • 2 years ago
  16. siddhantsharan Group Title
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    Does that seem correct so far? @Ishaan94

    • 2 years ago
  17. Ishaan94 Group Title
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    It does

    • 2 years ago
  18. siddhantsharan Group Title
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    |dw:1340389706521:dw| Writing the letters with spaces between them. And only putting S's in the spaces so as to ensure their seperation. Total ways of doing this ( S's together C's anyhow) : 5C2 * 4!/2!

    • 2 years ago
  19. Ishaan94 Group Title
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    And it also proves how simple this problem could be

    • 2 years ago
  20. Ishaan94 Group Title
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    And how stupid I think at times -sigh-

    • 2 years ago
  21. siddhantsharan Group Title
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    Yeah. It's pretty simple now.

    • 2 years ago
  22. Ishaan94 Group Title
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    Thank you

    • 2 years ago
  23. siddhantsharan Group Title
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    Anytime :)

    • 2 years ago
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