Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

RedPrince

  • 3 years ago

2x+y-3=0 x+2y+3=0 is these equations are solve like this:

  • This Question is Closed
  1. waterineyes
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    Multiply first equation by 2 4x + 2y - 6 = 0 x + 2y + 3 = 0 Subtract them: 3x = 9 x = 3 Put the value of x in any of the above equation and find the value of y.. Can you do it or not??

  2. RedPrince
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @waterineyes I want to solve it simultaneously: look \[x/(1)(-3) + (2)(3) = -y/(-3)(2) + (1)(3) = 1/(2)(2) +(1)(1)\]

  3. KRAZZy
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes waterineyes do it perfecly

  4. waterineyes
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    @KRAZZy What???

  5. RedPrince
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @KRAZZy I know and I also solve it! But I forgot that how to solve equations simultaneously!

  6. waterineyes
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    I studied this method but now forgot how to solve by this method but I will try wait for sometime...

  7. RedPrince
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @waterineyes O.k., I am waiting for your reply!!!

  8. KRAZZy
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    can any1 tell me wht is simultaneous methd:P

  9. zepp
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Are you referring to the reduction method?

  10. zepp
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    If so (x+2y+3=0)*2 = 2x+4y+6=0

  11. zepp
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1340608303151:dw|

  12. zepp
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    y=-3

  13. zepp
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ?

  14. waterineyes
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    Simultaneous Method says that: If two equations are like this: \[a_1x + b_1y + c_1 = 0\] \[a_2x + b_2y + c_2 = 0\] Then the method of Solving these equations by Cross Multiplication is: \[x/(b_1c_2 - b_2c_1) = y/((c_1a_2 - c_2a_1) = 1/(a_1b_2 - a_2b_1)\] Put in this the all the values and solve to get the values of x and y...

  15. waterineyes
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    So, according to our question: \[a_1 = 2, b_1 = 1, c_1 = -3, a_2 = 1, b_2 = 2, c_2 = 3\] Put these values in formula given above: \[x/(3 + 6) = y/(-3 -6) = 1/(4-1)\] \[x/9 = y/(-9) = 1/3\] Equating one by one: x/9 = 1/3 x = 3 And y/(-9) = 1/3 y = -3 So, (x, y) is (3, -3).....

  16. RedPrince
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @waterineyes @zepp @KRAZZy O.k., I get it! now I understand what is wrong! I am just putting + singn agter multiplying but there is -ive sign!!! thanks to all!!!!!

  17. waterineyes
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    Welcome dear..

  18. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy