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2x+y-3=0 x+2y+3=0 is these equations are solve like this:

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Multiply first equation by 2 4x + 2y - 6 = 0 x + 2y + 3 = 0 Subtract them: 3x = 9 x = 3 Put the value of x in any of the above equation and find the value of y.. Can you do it or not??
@waterineyes I want to solve it simultaneously: look \[x/(1)(-3) + (2)(3) = -y/(-3)(2) + (1)(3) = 1/(2)(2) +(1)(1)\]
yes waterineyes do it perfecly

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Other answers:

@KRAZZy What???
@KRAZZy I know and I also solve it! But I forgot that how to solve equations simultaneously!
I studied this method but now forgot how to solve by this method but I will try wait for sometime...
@waterineyes O.k., I am waiting for your reply!!!
can any1 tell me wht is simultaneous methd:P
Are you referring to the reduction method?
If so (x+2y+3=0)*2 = 2x+4y+6=0
Simultaneous Method says that: If two equations are like this: \[a_1x + b_1y + c_1 = 0\] \[a_2x + b_2y + c_2 = 0\] Then the method of Solving these equations by Cross Multiplication is: \[x/(b_1c_2 - b_2c_1) = y/((c_1a_2 - c_2a_1) = 1/(a_1b_2 - a_2b_1)\] Put in this the all the values and solve to get the values of x and y...
So, according to our question: \[a_1 = 2, b_1 = 1, c_1 = -3, a_2 = 1, b_2 = 2, c_2 = 3\] Put these values in formula given above: \[x/(3 + 6) = y/(-3 -6) = 1/(4-1)\] \[x/9 = y/(-9) = 1/3\] Equating one by one: x/9 = 1/3 x = 3 And y/(-9) = 1/3 y = -3 So, (x, y) is (3, -3).....
@waterineyes @zepp @KRAZZy O.k., I get it! now I understand what is wrong! I am just putting + singn agter multiplying but there is -ive sign!!! thanks to all!!!!!
Welcome dear..

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