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RedPrince
 2 years ago
2x+y3=0
x+2y+3=0
is these equations are solve like this:
RedPrince
 2 years ago
2x+y3=0 x+2y+3=0 is these equations are solve like this:

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waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.3Multiply first equation by 2 4x + 2y  6 = 0 x + 2y + 3 = 0 Subtract them: 3x = 9 x = 3 Put the value of x in any of the above equation and find the value of y.. Can you do it or not??

RedPrince
 2 years ago
Best ResponseYou've already chosen the best response.0@waterineyes I want to solve it simultaneously: look \[x/(1)(3) + (2)(3) = y/(3)(2) + (1)(3) = 1/(2)(2) +(1)(1)\]

KRAZZy
 2 years ago
Best ResponseYou've already chosen the best response.0yes waterineyes do it perfecly

RedPrince
 2 years ago
Best ResponseYou've already chosen the best response.0@KRAZZy I know and I also solve it! But I forgot that how to solve equations simultaneously!

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.3I studied this method but now forgot how to solve by this method but I will try wait for sometime...

RedPrince
 2 years ago
Best ResponseYou've already chosen the best response.0@waterineyes O.k., I am waiting for your reply!!!

KRAZZy
 2 years ago
Best ResponseYou've already chosen the best response.0can any1 tell me wht is simultaneous methd:P

zepp
 2 years ago
Best ResponseYou've already chosen the best response.0Are you referring to the reduction method?

zepp
 2 years ago
Best ResponseYou've already chosen the best response.0If so (x+2y+3=0)*2 = 2x+4y+6=0

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.3Simultaneous Method says that: If two equations are like this: \[a_1x + b_1y + c_1 = 0\] \[a_2x + b_2y + c_2 = 0\] Then the method of Solving these equations by Cross Multiplication is: \[x/(b_1c_2  b_2c_1) = y/((c_1a_2  c_2a_1) = 1/(a_1b_2  a_2b_1)\] Put in this the all the values and solve to get the values of x and y...

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.3So, according to our question: \[a_1 = 2, b_1 = 1, c_1 = 3, a_2 = 1, b_2 = 2, c_2 = 3\] Put these values in formula given above: \[x/(3 + 6) = y/(3 6) = 1/(41)\] \[x/9 = y/(9) = 1/3\] Equating one by one: x/9 = 1/3 x = 3 And y/(9) = 1/3 y = 3 So, (x, y) is (3, 3).....

RedPrince
 2 years ago
Best ResponseYou've already chosen the best response.0@waterineyes @zepp @KRAZZy O.k., I get it! now I understand what is wrong! I am just putting + singn agter multiplying but there is ive sign!!! thanks to all!!!!!
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