A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.3Multiply first equation by 2 4x + 2y  6 = 0 x + 2y + 3 = 0 Subtract them: 3x = 9 x = 3 Put the value of x in any of the above equation and find the value of y.. Can you do it or not??

RedPrince
 2 years ago
Best ResponseYou've already chosen the best response.0@waterineyes I want to solve it simultaneously: look \[x/(1)(3) + (2)(3) = y/(3)(2) + (1)(3) = 1/(2)(2) +(1)(1)\]

KRAZZy
 2 years ago
Best ResponseYou've already chosen the best response.0yes waterineyes do it perfecly

RedPrince
 2 years ago
Best ResponseYou've already chosen the best response.0@KRAZZy I know and I also solve it! But I forgot that how to solve equations simultaneously!

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.3I studied this method but now forgot how to solve by this method but I will try wait for sometime...

RedPrince
 2 years ago
Best ResponseYou've already chosen the best response.0@waterineyes O.k., I am waiting for your reply!!!

KRAZZy
 2 years ago
Best ResponseYou've already chosen the best response.0can any1 tell me wht is simultaneous methd:P

zepp
 2 years ago
Best ResponseYou've already chosen the best response.0Are you referring to the reduction method?

zepp
 2 years ago
Best ResponseYou've already chosen the best response.0If so (x+2y+3=0)*2 = 2x+4y+6=0

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.3Simultaneous Method says that: If two equations are like this: \[a_1x + b_1y + c_1 = 0\] \[a_2x + b_2y + c_2 = 0\] Then the method of Solving these equations by Cross Multiplication is: \[x/(b_1c_2  b_2c_1) = y/((c_1a_2  c_2a_1) = 1/(a_1b_2  a_2b_1)\] Put in this the all the values and solve to get the values of x and y...

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.3So, according to our question: \[a_1 = 2, b_1 = 1, c_1 = 3, a_2 = 1, b_2 = 2, c_2 = 3\] Put these values in formula given above: \[x/(3 + 6) = y/(3 6) = 1/(41)\] \[x/9 = y/(9) = 1/3\] Equating one by one: x/9 = 1/3 x = 3 And y/(9) = 1/3 y = 3 So, (x, y) is (3, 3).....

RedPrince
 2 years ago
Best ResponseYou've already chosen the best response.0@waterineyes @zepp @KRAZZy O.k., I get it! now I understand what is wrong! I am just putting + singn agter multiplying but there is ive sign!!! thanks to all!!!!!
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.