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tishara429
10-(2y-6)-y if y=8
->10-(2(8)- 6)-(8) -> 10-(16-6) -8 -> 10-(10)-8 -> 10- 10 -8 = -8
10-(2y-6)-y plug y=8 10-(2(8)-6)-8 10-(16-6)-8 10-10-8 0-8 -8
10-(2*8-6)-8 multiply 2 by 8 to get 16 10-(16-6)-8 subtract 6 from 16 to get 10. 10-(10)-8 multiply -1 by the 10 inside the parentheses. 10-10-8 subtract 10 from 10 to get 0. 0-8 Remove the 0 from the polynomial; adding for subtracting 0 does not change the value of expression. Answer -8