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Solve by factoring. 4x2 + 23x + 15 = 0

Mathematics
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ooh i like these
\[ax^2+bx+c=0\] So what you want to do is find factors of a*c that have product a*c and sum b.
(x+5)*(4*x+3)

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Other answers:

Good! Can you help me?
find two factors*
So what is a here? And what is b here? And what is c here?
\[4x ^{2}+23x+15=0\]
(x+5)*(4*x+3) x= -5 and -3/4 right
@timo86m I don't think it helps to give the answer. Can you explain how you got those factors?
A:x = 0.8 or x = -0.75 C:x = 0.75 or x = 5 B:x = -3 or x = -1.25 D:x = -0.75 or x = -5
@Makayla43 if you want to learn this, I'm trying to teach you.
What is a,b, and c in your equation?
(4x-3)(x-5)
@freckles what do you mean a,b,and c?
is that rite
it not right
\[ax^2+bx+c=0\] \[4x^2+23x+15=0\]
(x+5)*(4*x+3) if you not sure you can always expand this
Solve by factoring. -3x2 - x + 2 = 0
-(x+1)*(3*x-2)
\[-3x ^{2}-x+2=0\]
-3x2 - x + 2 = 0 you actually mean -3x^2 - x + 2 = 0
A:x = 0.5 or x = 0.33333 C:x = 1 or x = -0.66667 B:x = 0.33333 or x = -2 D:x = -1 or x = 0.66667
I think it d
You guys how is this teaching and how is this learning? Please try to teach @Makayla43 and not just give the answer. And @Makayla43 you shouldn't be just looking for answers. I think freckles here was trying to teach you how to do this.
Omg.
i teached, I said expand my factor if she doubts it lol.
But @timo86m how do you get the factors? Please explain that part so she will know how to do it.
Goodbye. He sent me a message a explained.
4x2 + 23x + 15 = 0 number that up to 15 and product is 23
To factor is mostly guess work that is where I draw the line :)
number that up to c and product is b coefficient. It is more important to show why it works then how to do something that is mostly guess work.

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