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ooh i like these

\[ax^2+bx+c=0\]
So what you want to do is find factors of a*c that have product a*c and sum b.

(x+5)*(4*x+3)

Good! Can you help me?

find two factors*

So what is a here?
And what is b here?
And what is c here?

\[4x ^{2}+23x+15=0\]

(x+5)*(4*x+3)
x= -5 and -3/4 right

A:x = 0.8 or x = -0.75 C:x = 0.75 or x = 5
B:x = -3 or x = -1.25 D:x = -0.75 or x = -5

@Makayla43 if you want to learn this, I'm trying to teach you.

What is a,b, and c in your equation?

@KNicksfan4life :D (:

(4x-3)(x-5)

is that rite

it not right

\[ax^2+bx+c=0\]
\[4x^2+23x+15=0\]

(x+5)*(4*x+3) if you not sure you can always expand this

Solve by factoring.
-3x2 - x + 2 = 0

-(x+1)*(3*x-2)

\[-3x ^{2}-x+2=0\]

-3x2 - x + 2 = 0
you actually mean
-3x^2 - x + 2 = 0

A:x = 0.5 or x = 0.33333 C:x = 1 or x = -0.66667
B:x = 0.33333 or x = -2 D:x = -1 or x = 0.66667

I think it d

Omg.

i teached, I said expand my factor if she doubts it lol.

Goodbye. He sent me a message a explained.

4x2 + 23x + 15 = 0
number that up to 15 and product is 23

To factor is mostly guess work that is where I draw the line :)