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edr1c Group Title

need some help in half wave rectification circuit, ...

  • 2 years ago
  • 2 years ago

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  1. edr1c Group Title
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    my set of question is like this, (question had specified it to be half-wave rectification) my expectation for the waveform from the output V1 is something like this: |dw:1340782227032:dw|

    • 2 years ago
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  2. edr1c Group Title
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    but i got this waveform which looks like clipping to me o.o

    • 2 years ago
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  3. kropot72 Group Title
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    During the positive half cycle of the input voltage the cathode of the diode is positive with respect to the anode. Therefore the diode cannot conduct and the positive half cycle will appear at the output. Durin the negative half cycle of the input voltage the diode conducts, clamping the output at about -0.7 volt. The diode needs a forward voltage of about 0.7 volt to enable it to conduct.

    • 2 years ago
  4. edr1c Group Title
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    ouh so it means i will still get -0.7v if i measure across the diode, and flat for the negative region for measuring across the resistor?

    • 2 years ago
  5. kropot72 Group Title
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    Do you intend to use an oscilloscope to measure these voltages?

    • 2 years ago
  6. edr1c Group Title
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    yea i used an oscilloscope to measure the output waveform.

    • 2 years ago
  7. kropot72 Group Title
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    You already have the voltage waveform across the diode. This waveform is -0.7 volts only during the negative half cycle of the input waveform. During the positive half cycle of the input voltage there is no conduction through the resistor and therefore no voltage across the resistor. The negative half cycles of the input voltage will be seen across the resistor.

    • 2 years ago
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