anonymous
  • anonymous
Factor completely by grouping 4x^2 + 12xy + 2x + 2y
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
first take out 2 2(2x^2 + 6xy + x+ y) -i cant see how this cant be factored any further - r u sure the question is correct?
anonymous
  • anonymous
Determine whether the following polynomials can be factored by grouping. If so, factor the polynomials showing all work. If not, explain why this method will not work. 4x2 + 12xy + 2x + 2y 3m2 + 6mn + 7m + 14n
anonymous
  • anonymous
Ok. TO factor by grouping, pair off the first two terms and last two terms. Then factor out the GCF from each pair. Since what's in the parentheses isn't the same, that's all you can do. 4x^2 + 12xy + 2x + 2y 4x(x + 3y) + 2(x + y)

Looking for something else?

Not the answer you are looking for? Search for more explanations.