A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 2 years ago
There is a nonuniform rod of length 2 m and mass 2 kg. It can freely rotate about one of its ends and the moment of inertia about this point is 4 kg*m^2. The center of gravity is 1.2 m from the pivot. What is the angular velocity as it reaches the vertical position if it is let go from rest in the horizontal position?
 2 years ago
There is a nonuniform rod of length 2 m and mass 2 kg. It can freely rotate about one of its ends and the moment of inertia about this point is 4 kg*m^2. The center of gravity is 1.2 m from the pivot. What is the angular velocity as it reaches the vertical position if it is let go from rest in the horizontal position?

This Question is Open

keshavsarda
 2 years ago
Best ResponseYou've already chosen the best response.0m*g*h=1/2*MI*\[\omega\]^2

meera_yadav
 2 years ago
Best ResponseYou've already chosen the best response.0hii, Methinks u can here use law of conservation of energy here. choosing potential energy equals to zero when it's at horizontal position , then initial total energy = energy at vertical position total energy at vertical position = \[I w ^{2}/2  mgh\] initial energy =0 substitute values u';; be there

CarlosGP
 2 years ago
Best ResponseYou've already chosen the best response.0The initial energy is given by the torque (momentum) M=mgd, where: m=mass, g=gravitational acceleration and d=distance of center of gravity. This momuntum is zero when gravitational force is aligned with the rod (vertical position) which means that has fully turned into rotational energy =1/2*I*w^2, then :w=SquareRoot(2mgd/I)

dianahla12
 2 years ago
Best ResponseYou've already chosen the best response.1Could you get the angular velocity from finding the angular acceleration though?\[ \alpha=\tau _{net}\times I\] You could get the angular acceleration from that.
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.