izzy777
please helpppp!!! Robin pulls a rope attached to a sled with a force of 50 N. The rope makes an angle of 30° with the ground, as shown below.
What force will move the sled vertically upwards?
183.4 N
25 N
43.3 N
100 N
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izzy777
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ganeshie8
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50/sin 30
izzy777
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wait i dont get it?
ganeshie8
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by applying 50N at an angle of 30 degrees, the sled is sliding horizontally, right ?
izzy777
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yes
ganeshie8
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so, if we apply the same force vertically, the slide will move up vertically
ganeshie8
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|dw:1340941337117:dw|
ganeshie8
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so, we need to calculate the value of "x" for which the vertical component becomes "50"
ganeshie8
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use trigonometry and find..
izzy777
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i don't know how to solve it...
izzy777
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im so confused
ganeshie8
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see the angle 30 once.
can you tell whats the opposite side for that angle ?
izzy777
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well one of the angles = 90 degrees the other one has to be60
ganeshie8
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|dw:1340941561296:dw|
ganeshie8
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\(\huge sin\ 30 = \frac{50}{x}\)
ganeshie8
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\(\huge x = \frac{50}{sin\ 30} = 100N\)
ganeshie8
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hope it is clear now... ?
izzy777
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yes! i think i get it now :) thank you so much can you help me with one more question?
ganeshie8
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sure..
izzy777
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A force of 8 N is exerted on a box. The component of this force which acts along the ground has a magnitude of 6.93 N, as shown below.
What is the measure of angle x?
40°
50°
60°
30°
izzy777
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ganeshie8
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use cosine
izzy777
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?
ganeshie8
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cos x = adj/hyp = 6.93/8
x = cos^-1(6.93/8) degrees