anonymous
  • anonymous
please helpppp!!! Robin pulls a rope attached to a sled with a force of 50 N. The rope makes an angle of 30° with the ground, as shown below. What force will move the sled vertically upwards? 183.4 N 25 N 43.3 N 100 N
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
ganeshie8
  • ganeshie8
50/sin 30
anonymous
  • anonymous
wait i dont get it?

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ganeshie8
  • ganeshie8
by applying 50N at an angle of 30 degrees, the sled is sliding horizontally, right ?
anonymous
  • anonymous
yes
ganeshie8
  • ganeshie8
so, if we apply the same force vertically, the slide will move up vertically
ganeshie8
  • ganeshie8
|dw:1340941337117:dw|
ganeshie8
  • ganeshie8
so, we need to calculate the value of "x" for which the vertical component becomes "50"
ganeshie8
  • ganeshie8
use trigonometry and find..
anonymous
  • anonymous
i don't know how to solve it...
anonymous
  • anonymous
im so confused
ganeshie8
  • ganeshie8
see the angle 30 once. can you tell whats the opposite side for that angle ?
anonymous
  • anonymous
well one of the angles = 90 degrees the other one has to be60
ganeshie8
  • ganeshie8
|dw:1340941561296:dw|
ganeshie8
  • ganeshie8
\(\huge sin\ 30 = \frac{50}{x}\)
ganeshie8
  • ganeshie8
\(\huge x = \frac{50}{sin\ 30} = 100N\)
ganeshie8
  • ganeshie8
hope it is clear now... ?
anonymous
  • anonymous
yes! i think i get it now :) thank you so much can you help me with one more question?
ganeshie8
  • ganeshie8
sure..
anonymous
  • anonymous
A force of 8 N is exerted on a box. The component of this force which acts along the ground has a magnitude of 6.93 N, as shown below. What is the measure of angle x? 40° 50° 60° 30°
anonymous
  • anonymous
ganeshie8
  • ganeshie8
use cosine
anonymous
  • anonymous
?
ganeshie8
  • ganeshie8
cos x = adj/hyp = 6.93/8 x = cos^-1(6.93/8) degrees

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