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IceWitch29

  • 3 years ago

Circle A has an equation of (x + 8)^2 + y^2 = 16. Where is the center of the circle located?

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  1. IceWitch29
    • 3 years ago
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    These are the answer choices: on the x-axis on the y-axis in the first quadrant in the third quadrant

  2. THE_PROPHET
    • 3 years ago
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    \[(x-a)^{2}+(y-b)^{2}=r^{2}\] be a circle...... then center is (a,b) in you case\[(x-(-8))^{2}+(y-0)^{2}=16\]

  3. THE_PROPHET
    • 3 years ago
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    so center is (-8,0)

  4. meera_yadav
    • 3 years ago
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    THE_PROPHET is absolutely correct !

  5. meera_yadav
    • 3 years ago
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    answer is on the x-axis:)

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