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 2 years ago
Circle A has an equation of (x + 8)^2 + y^2 = 16. Where is the center of the circle located?
 2 years ago
Circle A has an equation of (x + 8)^2 + y^2 = 16. Where is the center of the circle located?

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IceWitch29
 2 years ago
Best ResponseYou've already chosen the best response.0These are the answer choices: on the xaxis on the yaxis in the first quadrant in the third quadrant

THE_PROPHET
 2 years ago
Best ResponseYou've already chosen the best response.1\[(xa)^{2}+(yb)^{2}=r^{2}\] be a circle...... then center is (a,b) in you case\[(x(8))^{2}+(y0)^{2}=16\]

THE_PROPHET
 2 years ago
Best ResponseYou've already chosen the best response.1so center is (8,0)

meera_yadav
 2 years ago
Best ResponseYou've already chosen the best response.0THE_PROPHET is absolutely correct !

meera_yadav
 2 years ago
Best ResponseYou've already chosen the best response.0answer is on the xaxis:)
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