Here's the question you clicked on:
IceWitch29
Circle A has an equation of (x + 8)^2 + y^2 = 16. Where is the center of the circle located?
These are the answer choices: on the x-axis on the y-axis in the first quadrant in the third quadrant
\[(x-a)^{2}+(y-b)^{2}=r^{2}\] be a circle...... then center is (a,b) in you case\[(x-(-8))^{2}+(y-0)^{2}=16\]
so center is (-8,0)
THE_PROPHET is absolutely correct !
answer is on the x-axis:)