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IceWitch29
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Circle A has an equation of (x + 8)^2 + y^2 = 16. Where is the center of the circle located?
 2 years ago
 2 years ago
IceWitch29 Group Title
Circle A has an equation of (x + 8)^2 + y^2 = 16. Where is the center of the circle located?
 2 years ago
 2 years ago

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IceWitch29 Group TitleBest ResponseYou've already chosen the best response.0
These are the answer choices: on the xaxis on the yaxis in the first quadrant in the third quadrant
 2 years ago

THE_PROPHET Group TitleBest ResponseYou've already chosen the best response.1
\[(xa)^{2}+(yb)^{2}=r^{2}\] be a circle...... then center is (a,b) in you case\[(x(8))^{2}+(y0)^{2}=16\]
 2 years ago

THE_PROPHET Group TitleBest ResponseYou've already chosen the best response.1
so center is (8,0)
 2 years ago

meera_yadav Group TitleBest ResponseYou've already chosen the best response.0
THE_PROPHET is absolutely correct !
 2 years ago

meera_yadav Group TitleBest ResponseYou've already chosen the best response.0
answer is on the xaxis:)
 2 years ago
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