Find the derivative:
sin(xcosx)
so the answer is after being simplified (cosx-xsinx)cos(xcosx)
I have no idea. how.

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this is chain rule

\[\frac{dy}{dx}=\frac{dy}{du}\frac{du}{dx}\] where your y=sin(u) and your u=xcos(x)

ok so:
sin(xcosx)(-sinx)(1)+cos(xcosx)

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