A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.0here's my thought let x  1 = a therefore a +1 = x 2a^3 = a + 1 + 1 2a^3 = a + 2 2a^3  a  2 = 0 does that give you any ideas?

louis413
 2 years ago
Best ResponseYou've already chosen the best response.02(x1)^3=x+1 noo sorry not really can u tell me how to do it just by factoring etc?

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.0lol that's what im thinking too

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.0@myininaya pls help here

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2Hey @lgbasallote what was wrong with your way?

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2It seems to be awesome! :)

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.0i don't know what to do next lol

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2Try doing a little of testing possible rational zeros for what you have

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2Synthetic division will come in handy

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.0you heard her @louis413 ;)

louis413
 2 years ago
Best ResponseYou've already chosen the best response.0lol im only in alg/trig in high schooll.. loll wut is that?

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2oh wait i think i made a mistake anyways... let me try again but yeah that is what i would do test to see if any possible rational zeros work

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2algebra/trig? which one?

louis413
 2 years ago
Best ResponseYou've already chosen the best response.0well im takling the algebra2/trig course right now at summer school

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2synthetic division and looking at possible rational zeros are in algebra

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2ok so what have you learned then?

louis413
 2 years ago
Best ResponseYou've already chosen the best response.0factoring... quadratic formula completeing the squares etc

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2And is your equation written correctly?

louis413
 2 years ago
Best ResponseYou've already chosen the best response.0yes can it be solved like 2(x1)^2(x1)1(X1)=0

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2I can only see to find a real approximation by looking at the graph and seeing where it crosses the xaxis

shubhamsrg
 2 years ago
Best ResponseYou've already chosen the best response.3would you like to go for a trignometric solution? might seem complicated but is easy.. involves inverse function just a bit..and sin 3x etc formullas ?

shubhamsrg
 2 years ago
Best ResponseYou've already chosen the best response.3well.. in 2a^3  a  2 = 0 let a = m sin y => 2m^3 sin^3 y  msin y 2 =0 multiplying both sides by (2/m^3) => 4sin^3 y + 2sin y/(m^2) + 4/(m^3) =0 our aim is to convert this in the form of 4sin^3 y + 3 siny which will convert it into sin 3y and simplify things we have to chose a particular value of m for that purpose in our case 2/m^2 = 3 or m = sqrt(3/2) and sqrt(3/2) thus we have these 2 eqns : 4sin^3 y + 3sin y + 8sqrt(2)/(3sqrt(3)) = 0 and 4sin^3 y + 3sin y  8sqrt(2)/(3sqrt(3)) = 0 => sin 3y =  8sqrt(2)/(3sqrt(3)) and =>sin 3y = 8sqrt(2)/(3sqrt(3)) now using any scientific calculator, we may find value of y,then a(=msin y) and then finally x(=a+1)

shubhamsrg
 2 years ago
Best ResponseYou've already chosen the best response.3hope i was able to explain well..
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.