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lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.0here's my thought let x  1 = a therefore a +1 = x 2a^3 = a + 1 + 1 2a^3 = a + 2 2a^3  a  2 = 0 does that give you any ideas?

louis413
 2 years ago
Best ResponseYou've already chosen the best response.02(x1)^3=x+1 noo sorry not really can u tell me how to do it just by factoring etc?

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.0lol that's what im thinking too

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.0@myininaya pls help here

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2Hey @lgbasallote what was wrong with your way?

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2It seems to be awesome! :)

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.0i don't know what to do next lol

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2Try doing a little of testing possible rational zeros for what you have

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2Synthetic division will come in handy

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.0you heard her @louis413 ;)

louis413
 2 years ago
Best ResponseYou've already chosen the best response.0lol im only in alg/trig in high schooll.. loll wut is that?

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2oh wait i think i made a mistake anyways... let me try again but yeah that is what i would do test to see if any possible rational zeros work

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2algebra/trig? which one?

louis413
 2 years ago
Best ResponseYou've already chosen the best response.0well im takling the algebra2/trig course right now at summer school

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2synthetic division and looking at possible rational zeros are in algebra

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2ok so what have you learned then?

louis413
 2 years ago
Best ResponseYou've already chosen the best response.0factoring... quadratic formula completeing the squares etc

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2And is your equation written correctly?

louis413
 2 years ago
Best ResponseYou've already chosen the best response.0yes can it be solved like 2(x1)^2(x1)1(X1)=0

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.2I can only see to find a real approximation by looking at the graph and seeing where it crosses the xaxis

shubhamsrg
 2 years ago
Best ResponseYou've already chosen the best response.3would you like to go for a trignometric solution? might seem complicated but is easy.. involves inverse function just a bit..and sin 3x etc formullas ?

shubhamsrg
 2 years ago
Best ResponseYou've already chosen the best response.3well.. in 2a^3  a  2 = 0 let a = m sin y => 2m^3 sin^3 y  msin y 2 =0 multiplying both sides by (2/m^3) => 4sin^3 y + 2sin y/(m^2) + 4/(m^3) =0 our aim is to convert this in the form of 4sin^3 y + 3 siny which will convert it into sin 3y and simplify things we have to chose a particular value of m for that purpose in our case 2/m^2 = 3 or m = sqrt(3/2) and sqrt(3/2) thus we have these 2 eqns : 4sin^3 y + 3sin y + 8sqrt(2)/(3sqrt(3)) = 0 and 4sin^3 y + 3sin y  8sqrt(2)/(3sqrt(3)) = 0 => sin 3y =  8sqrt(2)/(3sqrt(3)) and =>sin 3y = 8sqrt(2)/(3sqrt(3)) now using any scientific calculator, we may find value of y,then a(=msin y) and then finally x(=a+1)

shubhamsrg
 2 years ago
Best ResponseYou've already chosen the best response.3hope i was able to explain well..
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