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Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.0
Hint: similar to your other one.
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.0
But this is apparently an integral which does not have a close form..
 2 years ago

wasiqss Group TitleBest ResponseYou've already chosen the best response.1
ash dont solve its for me
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
I ain't solving, just for reference http://www.wolframalpha.com/input/?i=integral+1%2F%28ln+%28x%2B1%29%29+dx
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.0
this is like wasiqs previous integral which was apparently solveable http://www.wolframalpha.com/input/?i=integral+e^x%2F%28x%29
 2 years ago

wasiqss Group TitleBest ResponseYou've already chosen the best response.1
mishoo it was easy ~~~ i did it
 2 years ago

wasiqss Group TitleBest ResponseYou've already chosen the best response.1
just apply by parts
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.0
by parts? please elaborate.
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.0
i thought the first step is a substitution..
 2 years ago

wasiqss Group TitleBest ResponseYou've already chosen the best response.1
yeh take 1 as first functio
 2 years ago

wasiqss Group TitleBest ResponseYou've already chosen the best response.1
\[x/{(\ln(x+1)}  \int\limits_{}^{}x^2 +x\]
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.0
how about \(u= ln(x+1)\) => \(e^{u}= x+1\)
 2 years ago

wasiqss Group TitleBest ResponseYou've already chosen the best response.1
if it can be done easily why take substitution..
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.0
but this is an integral which does not have a closed form right?
 2 years ago

wasiqss Group TitleBest ResponseYou've already chosen the best response.1
i dont understand forms :P i just know how to solve the ugliest of integrals :P
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.0
lol, but look at the answer on wolfram..
 2 years ago

wasiqss Group TitleBest ResponseYou've already chosen the best response.1
i dont trust wolfram cause in two questions i pointed out its mistake and did what it cant do :P
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.0
lol are you sure that you're right though? :P
 2 years ago

wasiqss Group TitleBest ResponseYou've already chosen the best response.1
i can do better than wolfram :P
 2 years ago
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