Mimi_x3
\[\int\frac{1}{ln(x+1)}
dx\]



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Mimi_x3
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@wasiqss

wasiqss
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lemme try

Mimi_x3
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Hint: similar to your other one.

Mimi_x3
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But this is apparently an integral which does not have a close form..

wasiqss
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okay

wasiqss
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ash dont solve its for me



wasiqss
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mishoo it was easy ~~~ i did it

wasiqss
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just apply by parts

Mimi_x3
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by parts? please elaborate.

Mimi_x3
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i thought the first step is a substitution..

wasiqss
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yeh take 1 as first functio

wasiqss
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\[x/{(\ln(x+1)}  \int\limits_{}^{}x^2 +x\]

Mimi_x3
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how about \(u= ln(x+1)\) => \(e^{u}= x+1\)

wasiqss
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if it can be done easily why take substitution..

Mimi_x3
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but this is an integral which does not have a closed form right?

wasiqss
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i dont understand forms :P i just know how to solve the ugliest of integrals :P

Mimi_x3
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lol, but look at the answer on wolfram..

wasiqss
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i dont trust wolfram cause in two questions i pointed out its mistake and did what it cant do :P

Mimi_x3
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lol are you sure that you're right though? :P

wasiqss
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i can do better than wolfram :P

Mimi_x3
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lol