Mimi_x3
  • Mimi_x3
\[\int\frac{1}{ln(x+1)} dx\]
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Mimi_x3
  • Mimi_x3
@wasiqss
wasiqss
  • wasiqss
lemme try
Mimi_x3
  • Mimi_x3
Hint: similar to your other one.

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More answers

Mimi_x3
  • Mimi_x3
But this is apparently an integral which does not have a close form..
wasiqss
  • wasiqss
okay
wasiqss
  • wasiqss
ash dont solve its for me
ash2326
  • ash2326
I ain't solving, just for reference http://www.wolframalpha.com/input/?i=integral+1%2F%28ln+%28x%2B1%29%29+dx
Mimi_x3
  • Mimi_x3
this is like wasiqs previous integral which was apparently solveable http://www.wolframalpha.com/input/?i=integral+e^x%2F%28x%29
wasiqss
  • wasiqss
mishoo it was easy ~~~ i did it
wasiqss
  • wasiqss
just apply by parts
Mimi_x3
  • Mimi_x3
by parts? please elaborate.
Mimi_x3
  • Mimi_x3
i thought the first step is a substitution..
wasiqss
  • wasiqss
yeh take 1 as first functio
wasiqss
  • wasiqss
\[x/{(\ln(x+1)} - \int\limits_{}^{}x^2 +x\]
Mimi_x3
  • Mimi_x3
how about \(u= ln(x+1)\) => \(e^{u}= x+1\)
wasiqss
  • wasiqss
if it can be done easily why take substitution..
Mimi_x3
  • Mimi_x3
but this is an integral which does not have a closed form right?
wasiqss
  • wasiqss
i dont understand forms :P i just know how to solve the ugliest of integrals :P
Mimi_x3
  • Mimi_x3
lol, but look at the answer on wolfram..
wasiqss
  • wasiqss
i dont trust wolfram cause in two questions i pointed out its mistake and did what it cant do :P
Mimi_x3
  • Mimi_x3
lol are you sure that you're right though? :P
wasiqss
  • wasiqss
i can do better than wolfram :P
Mimi_x3
  • Mimi_x3
lol

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