## Mimi_x3 2 years ago $\int\frac{1}{ln(x+1)} dx$

1. Mimi_x3

@wasiqss

2. wasiqss

lemme try

3. Mimi_x3

Hint: similar to your other one.

4. Mimi_x3

But this is apparently an integral which does not have a close form..

5. wasiqss

okay

6. wasiqss

ash dont solve its for me

7. ash2326

I ain't solving, just for reference http://www.wolframalpha.com/input/?i=integral+1%2F%28ln+%28x%2B1%29%29+dx

8. Mimi_x3

this is like wasiqs previous integral which was apparently solveable http://www.wolframalpha.com/input/?i=integral+e^x%2F%28x%29

9. wasiqss

mishoo it was easy ~~~ i did it

10. wasiqss

just apply by parts

11. Mimi_x3

12. Mimi_x3

i thought the first step is a substitution..

13. wasiqss

yeh take 1 as first functio

14. wasiqss

$x/{(\ln(x+1)} - \int\limits_{}^{}x^2 +x$

15. Mimi_x3

how about $$u= ln(x+1)$$ => $$e^{u}= x+1$$

16. wasiqss

if it can be done easily why take substitution..

17. Mimi_x3

but this is an integral which does not have a closed form right?

18. wasiqss

i dont understand forms :P i just know how to solve the ugliest of integrals :P

19. Mimi_x3

lol, but look at the answer on wolfram..

20. wasiqss

i dont trust wolfram cause in two questions i pointed out its mistake and did what it cant do :P

21. Mimi_x3

lol are you sure that you're right though? :P

22. wasiqss

i can do better than wolfram :P

23. Mimi_x3

lol