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anonymous
 4 years ago
Jimmy’s proof:
Statement 1: In triangle ADC and BCD, AD = BC (opposite sides of a rectangle are congruent)
Statement 2: Angle ADC = Angle BCD (angles of a rectangle are 90°)
Statement 3: DC=DC (transitive property of equality)
Statement 4: Triangle ADC and BCD are congruent (by SAS postulate)
Statement 5: AC = BD (by CPCTC)
Which statement in Jimmy’s proof has an error?
anonymous
 4 years ago
Jimmy’s proof: Statement 1: In triangle ADC and BCD, AD = BC (opposite sides of a rectangle are congruent) Statement 2: Angle ADC = Angle BCD (angles of a rectangle are 90°) Statement 3: DC=DC (transitive property of equality) Statement 4: Triangle ADC and BCD are congruent (by SAS postulate) Statement 5: AC = BD (by CPCTC) Which statement in Jimmy’s proof has an error?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah apparently there is no error !!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yippee!!Cheers for Jimmy!!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no i think there can be a mistake in statement five ..... if you consider each statement independent of each other then in statement 5 the student have not mentioned the congruent triangle so may be it can be considered as incorrect ever though the relation is correct

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I guess.. there could be an error in statement 1 , where he says that "opposite sides of a rectangle are congruent)" but .. as far as i know, you never say they are 'congruent', you always say they are 'equal'! :/

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if u consider each statement independent then statement 4 is also wrong as u cannot say 2 triangles are congruent without proof or reason.....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thats CPCTC may be incorrect ....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0as far as i know its CPCT[Corresponding Parts of Congruent Triangles] NOT CPCTC

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0nah CPCTC is rite its [Corresponding Parts of Congruent Triangles are Congruent]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@Hashir : Naah, 'CPCTC' is absolutely correct.. because.. he already proved that the 2 triangles are equal by SAS postulate..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i am saying that there may be a possibility .... if we consider each statement independent

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0CPCTC ('Corresponding parts of congruent triangles are congruent') is nothing but another name/abbr. for CPCT ..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Okay Conclusion:Jimmy is an overcautious idiot trying to find a mistake in an absolutely correct proof!!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so 3 has a problem ... 3 is incorrect ... got it now

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0whats wrong in 3??DC=DC is not true?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0bro in transitive property we prove that if a=b and b=c then a=c .... not a=a !!!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it doesnt make any sense

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@Hashir : I totally agree with you!!.. transitive property is > if a=b, and b=c .. a=c! :P

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it can be correct if he says that DC=CD

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but he didnt say that

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh!ok!i did not know that!!so yes Jimmy being overcautious helped him as @Hashir the detective finds the criminal eluding his 2 pardnas!
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