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anonymous
 3 years ago
This is a word problem involving simple interest: Pat invested $3000, part went into an acct that paid 10% simple annual interest, and another part went into an acct that paid 8% simple annual interest. If the total interest at the end of the year was $256, how much with the investment in each acct at the beginning of the year?
anonymous
 3 years ago
This is a word problem involving simple interest: Pat invested $3000, part went into an acct that paid 10% simple annual interest, and another part went into an acct that paid 8% simple annual interest. If the total interest at the end of the year was $256, how much with the investment in each acct at the beginning of the year?

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slaaibak
 3 years ago
Best ResponseYou've already chosen the best response.0x(.08) + (3000  x)(1.1) = 256 Solve that.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Does the 1.1 come from the 10% part?

slaaibak
 3 years ago
Best ResponseYou've already chosen the best response.0Sorry I made a typo. It should be x(.08) + (3000  x)(0.1) = 256 where the .08 is from the 8% and the 0.1 is from the 10%

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I think I'm messing this up somehow... I ended up with X= 11,300. LOL I know that's not right

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@Limitless , can you help me?
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