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michelle1503
 3 years ago
can someone please explain to me when rational functions do not cross and when they do cross their horizontal asypmtote. I thought the rational function can never reach, only approach an asymptote but some rational functions completely cross their horizontal asymptote and i dont understand why this sometimes happens?
michelle1503
 3 years ago
can someone please explain to me when rational functions do not cross and when they do cross their horizontal asypmtote. I thought the rational function can never reach, only approach an asymptote but some rational functions completely cross their horizontal asymptote and i dont understand why this sometimes happens?

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Posideon
 3 years ago
Best ResponseYou've already chosen the best response.0give us an example of such a function. Never heard of such a function.

slaaibak
 3 years ago
Best ResponseYou've already chosen the best response.1A south african! Greetings! Poseidon, they do exist, i'll give an example in a sec

slaaibak
 3 years ago
Best ResponseYou've already chosen the best response.1Remember, a horisontal asymptote is there to show that the function goes to a limit when x goes to + infinity. Will try to explain better now

michelle1503
 3 years ago
Best ResponseYou've already chosen the best response.0okay... \[f(x)=(x^25x+4)/(x^24)\]

michelle1503
 3 years ago
Best ResponseYou've already chosen the best response.0hahaha your South African? haha.. awesome :) sweet thanks ill wait :)

michelle1503
 3 years ago
Best ResponseYou've already chosen the best response.0LOL i can see by your name that you are LOOL BRILLIANT :)

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1Typing too fast is what did it

slaaibak
 3 years ago
Best ResponseYou've already chosen the best response.1hero, it factors into (x2) (x+2)

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1Which means no relevant asymptote has been crossed

slaaibak
 3 years ago
Best ResponseYou've already chosen the best response.1Anyways. The explanation: The horizontal asymptote simply shows us the limit of the function when x tends to + infinity. Now this really doesn't tell us anything about the function not evaluated in the extremities.

slaaibak
 3 years ago
Best ResponseYou've already chosen the best response.1Hero, I am not sure how you deduce that. but it's false.

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1slaaibak, I was referring to the vertical asymptotes. Stop making it look like I don't know what I'm talking about. I hate when people try to belittle others. I meant that the function doesn't cross the vertical asymptotes.

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1Stop trying to disagree with what I say and concentrate on actually helping the student.

michelle1503
 3 years ago
Best ResponseYou've already chosen the best response.0okay understood that it shows the limit of the function. BUT... the horizontal asymptote is y=1 and in the graph it is crossed... i dont get that ... and other graghs the Horizontal asymptote isnt crossed... what i wana know is what parts of the graph uses the horizontal asymptote as a limit as x reaches + infinity and which parts of the graph just ignores the H.A and resembles itself as a cubic function...explain that to me.. if you understand what im trying to say lol

slaaibak
 3 years ago
Best ResponseYou've already chosen the best response.1The horizontal asymptote is used for x when x tends to +infinity. That means, very very very large values of x uses it as an asymptote. In words, the asymptote is something that, if you take very large values of x, the graph/function value converges to a yvalue. I'll draw something quickly

slaaibak
 3 years ago
Best ResponseYou've already chosen the best response.1At the two circles is what I'm trying to show. The asymptote is showing the behavior of the function when x gets either very small or very large. But, this is important, the horisontal asymptotes say nothing about the "finite" values of the function. Meaning, apart from infinity, the graph my cross the horizontal asymptote

michelle1503
 3 years ago
Best ResponseYou've already chosen the best response.0lol thanks that made a lot of sense now haha... thanks for the help :)

slaaibak
 3 years ago
Best ResponseYou've already chosen the best response.1haha sure :) just ask if theres anything else ! oh and I hope you're not a blue bull. or pink :/

michelle1503
 3 years ago
Best ResponseYou've already chosen the best response.0hahahahaha oh GOD you better not be a stormer or a sharkie.....

michelle1503
 3 years ago
Best ResponseYou've already chosen the best response.0haha thanks will do :)

slaaibak
 3 years ago
Best ResponseYou've already chosen the best response.1We all know the stormers will win :)

michelle1503
 3 years ago
Best ResponseYou've already chosen the best response.0hahaha YOU WISHHHH... you stole habbana from us... pfft

slaaibak
 3 years ago
Best ResponseYou've already chosen the best response.1I think of it as: He came to his senses...

michelle1503
 3 years ago
Best ResponseYou've already chosen the best response.0dont make me unfan you grr lol :)

slaaibak
 3 years ago
Best ResponseYou've already chosen the best response.1haha who's going to help you then :)

precal
 3 years ago
Best ResponseYou've already chosen the best response.1To determine if the function crosses a horizontal asymptote: Set function equal to the horizontal asymptote and solve it.

precal
 3 years ago
Best ResponseYou've already chosen the best response.1example:dw:1341174113051:dw the horizontal asym is y=3

precal
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1341174156180:dw you will see that the function does cross the horizontal asymptote at (6, 3)

precal
 3 years ago
Best ResponseYou've already chosen the best response.1Note: As hero stated, functions never cross the vertical asymptotes.

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1Well, thank goodness someone supports me.

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1Not everyone thinks I'm a fool apparently.

precal
 3 years ago
Best ResponseYou've already chosen the best response.1@Hero You are the best :)
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