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lyssa

  • 2 years ago

What are the solution intervals for |2x – 1| + 6 > 9?

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  1. lyssa
    • 2 years ago
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    I need help just figuring it out

  2. zepp
    • 2 years ago
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    Like @asnaseer did, simplify this inequality. \(|2x-1|+6-6>9-6\\|2x-1|>3\) And now you may proceed to setting up two inequations.

  3. zepp
    • 2 years ago
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    Do you know how to set up those inequations?

  4. lyssa
    • 2 years ago
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    2x-1>3 2x>4 x>2 -2x-1<-3 -2x<-2 x>1 Are these right?

  5. zepp
    • 2 years ago
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    Excellent! :)

  6. lyssa
    • 2 years ago
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    but here is the choices A.x < –1 or x > 2 B.x < 1 or x > –2 C.x > –1 and x < 2 D.x > 1 and x < –2

  7. zepp
    • 2 years ago
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    Although the negative one is wrong -------------------- \(2x-1<-3\\2x<-2\\x<\frac{-2}{2}\\x<-1\)

  8. lyssa
    • 2 years ago
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    So it is A?

  9. zepp
    • 2 years ago
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    Since the absolute value of \(2x-1\) must be greater than 3, \(2x-1\) could be in the negative side too, -4,-5,-6,-7 and so on, because when you take the absolute value of these, you get something greater than 3.

  10. zepp
    • 2 years ago
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    Yes.

  11. lyssa
    • 2 years ago
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    Thanks sooo much:D I have more questions maybe you could help with them too:D

  12. zepp
    • 2 years ago
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    Sure :)

  13. lyssa
    • 2 years ago
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    K i will post them as a new question:D

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