Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

What are the solution intervals for |2x – 1| + 6 > 9?

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

I need help just figuring it out
Like @asnaseer did, simplify this inequality. \(|2x-1|+6-6>9-6\\|2x-1|>3\) And now you may proceed to setting up two inequations.
Do you know how to set up those inequations?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

2x-1>3 2x>4 x>2 -2x-1<-3 -2x<-2 x>1 Are these right?
Excellent! :)
but here is the choices A.x < –1 or x > 2 B.x < 1 or x > –2 C.x > –1 and x < 2 D.x > 1 and x < –2
Although the negative one is wrong -------------------- \(2x-1<-3\\2x<-2\\x<\frac{-2}{2}\\x<-1\)
So it is A?
Since the absolute value of \(2x-1\) must be greater than 3, \(2x-1\) could be in the negative side too, -4,-5,-6,-7 and so on, because when you take the absolute value of these, you get something greater than 3.
Yes.
Thanks sooo much:D I have more questions maybe you could help with them too:D
Sure :)
K i will post them as a new question:D

Not the answer you are looking for?

Search for more explanations.

Ask your own question