anonymous
  • anonymous
What are the solution intervals for |2x – 1| + 6 > 9?
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
I need help just figuring it out
zepp
  • zepp
Like @asnaseer did, simplify this inequality. \(|2x-1|+6-6>9-6\\|2x-1|>3\) And now you may proceed to setting up two inequations.
zepp
  • zepp
Do you know how to set up those inequations?

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anonymous
  • anonymous
2x-1>3 2x>4 x>2 -2x-1<-3 -2x<-2 x>1 Are these right?
zepp
  • zepp
Excellent! :)
anonymous
  • anonymous
but here is the choices A.x < –1 or x > 2 B.x < 1 or x > –2 C.x > –1 and x < 2 D.x > 1 and x < –2
zepp
  • zepp
Although the negative one is wrong -------------------- \(2x-1<-3\\2x<-2\\x<\frac{-2}{2}\\x<-1\)
anonymous
  • anonymous
So it is A?
zepp
  • zepp
Since the absolute value of \(2x-1\) must be greater than 3, \(2x-1\) could be in the negative side too, -4,-5,-6,-7 and so on, because when you take the absolute value of these, you get something greater than 3.
zepp
  • zepp
Yes.
anonymous
  • anonymous
Thanks sooo much:D I have more questions maybe you could help with them too:D
zepp
  • zepp
Sure :)
anonymous
  • anonymous
K i will post them as a new question:D

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