## lyssa 3 years ago What are the solution intervals for |2x – 1| + 6 > 9?

1. lyssa

I need help just figuring it out

2. zepp

Like @asnaseer did, simplify this inequality. $$|2x-1|+6-6>9-6\\|2x-1|>3$$ And now you may proceed to setting up two inequations.

3. zepp

Do you know how to set up those inequations?

4. lyssa

2x-1>3 2x>4 x>2 -2x-1<-3 -2x<-2 x>1 Are these right?

5. zepp

Excellent! :)

6. lyssa

but here is the choices A.x < –1 or x > 2 B.x < 1 or x > –2 C.x > –1 and x < 2 D.x > 1 and x < –2

7. zepp

Although the negative one is wrong -------------------- $$2x-1<-3\\2x<-2\\x<\frac{-2}{2}\\x<-1$$

8. lyssa

So it is A?

9. zepp

Since the absolute value of $$2x-1$$ must be greater than 3, $$2x-1$$ could be in the negative side too, -4,-5,-6,-7 and so on, because when you take the absolute value of these, you get something greater than 3.

10. zepp

Yes.

11. lyssa

Thanks sooo much:D I have more questions maybe you could help with them too:D

12. zepp

Sure :)

13. lyssa

K i will post them as a new question:D