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forever_confused
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Can you find what is being oxidized and reduced (including their oxidation numbers), the oxidizing agent, and reducing agent for CH4 + 2O2 CO2 + 2H2O.
 2 years ago
 2 years ago
forever_confused Group Title
Can you find what is being oxidized and reduced (including their oxidation numbers), the oxidizing agent, and reducing agent for CH4 + 2O2 CO2 + 2H2O.
 2 years ago
 2 years ago

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Theo177 Group TitleBest ResponseYou've already chosen the best response.0
The equation has the correct numbers, you dont need to change anyghing. CH4 is oxidized. O2 is the oxidised agent CO2 is the reducing agent I think.
 2 years ago

forever_confused Group TitleBest ResponseYou've already chosen the best response.0
So nothing has oxidation numbers?
 2 years ago

forever_confused Group TitleBest ResponseYou've already chosen the best response.0
CH4 + 2O2 > CO2 + 2H2O sorry if me forgetting the yield sign confused you
 2 years ago

Theo177 Group TitleBest ResponseYou've already chosen the best response.0
Oh wait, I though you were talking about the equation numbers. I am not sure about the axidation numbers.
 2 years ago

forever_confused Group TitleBest ResponseYou've already chosen the best response.0
Hm, no the oxidation numbers :/ I'm not sure. Like, would I solve the oxidation numbers for each one.. Like CH4 and then 2O2 and so on?
 2 years ago

Theo177 Group TitleBest ResponseYou've already chosen the best response.0
I m not sure about the oxidation numbers either, sry... gtg, I have some math exams right now:p. I think I m gonna fail so hard :P
 2 years ago

forever_confused Group TitleBest ResponseYou've already chosen the best response.0
its fine. and thanks a lot. Good luck! You seem really smart (: You'll do fine
 2 years ago

meera_yadav Group TitleBest ResponseYou've already chosen the best response.0
dw:1341216983942:dw
 2 years ago

meera_yadav Group TitleBest ResponseYou've already chosen the best response.0
hii, if u need any clarifications then let me know !!
 2 years ago

meera_yadav Group TitleBest ResponseYou've already chosen the best response.0
here , C has oxidation no. = 4 in CH4 (since H has +1 oxidation state), while it's +4 in CO2 ( since O has 2 oxidation state) while O is in zero oxidation state in O2 (as oxidation states of elements in free state is zero) and 2 in H2O
 2 years ago
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