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dividing fractions is like multiple the inverse :
(3/x^2) * (x^3/1)

so can you solve it now ?

3x^3/x^2

but then how would you get the restrictions

ok .. but you can go further .. using : x^m/x^n = x^(m-n)

so your expression will become : 3x^(3-2) = 3x

but.. you must remember that when you started there was x^3 in the denominator
so x is not 0

x^3 and x^2 in the denominators

im so confused so would the simplified form be just 3x?

friend see my attachment i hope it helps.

so i was right?? It is 3x?!

yes friend you were right.

yaaay thank you:)