A community for students.
Here's the question you clicked on:
 0 viewing
iamawfulatmath3
 2 years ago
What is the simplified form of (3/x^2) / (1/x^3)
iamawfulatmath3
 2 years ago
What is the simplified form of (3/x^2) / (1/x^3)

This Question is Closed

Coolsector
 2 years ago
Best ResponseYou've already chosen the best response.0dividing fractions is like multiple the inverse : (3/x^2) * (x^3/1)

Coolsector
 2 years ago
Best ResponseYou've already chosen the best response.0so can you solve it now ?

iamawfulatmath3
 2 years ago
Best ResponseYou've already chosen the best response.0but then how would you get the restrictions

Coolsector
 2 years ago
Best ResponseYou've already chosen the best response.0ok .. but you can go further .. using : x^m/x^n = x^(mn)

Coolsector
 2 years ago
Best ResponseYou've already chosen the best response.0so your expression will become : 3x^(32) = 3x

Coolsector
 2 years ago
Best ResponseYou've already chosen the best response.0but.. you must remember that when you started there was x^3 in the denominator so x is not 0

Coolsector
 2 years ago
Best ResponseYou've already chosen the best response.0x^3 and x^2 in the denominators

iamawfulatmath3
 2 years ago
Best ResponseYou've already chosen the best response.0im so confused so would the simplified form be just 3x?

muhammad9t5
 2 years ago
Best ResponseYou've already chosen the best response.1friend see my attachment i hope it helps.

iamawfulatmath3
 2 years ago
Best ResponseYou've already chosen the best response.0so i was right?? It is 3x?!

muhammad9t5
 2 years ago
Best ResponseYou've already chosen the best response.1yes friend you were right.

iamawfulatmath3
 2 years ago
Best ResponseYou've already chosen the best response.0yaaay thank you:)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.