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angela210793
 4 years ago
@Everyone that can and wants to help me pass the exam...
angela210793
 4 years ago
@Everyone that can and wants to help me pass the exam...

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Right here for you :)

angela210793
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1341258864115:dw

angela210793
 4 years ago
Best ResponseYou've already chosen the best response.0lol...tht's how everything is in my book...

angela210793
 4 years ago
Best ResponseYou've already chosen the best response.0ok..here's another onedw:1341259083895:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0let \[t=\tan \frac{x}{2}\]

angela210793
 4 years ago
Best ResponseYou've already chosen the best response.0can u go on please...im not good at integrals especially when u get t=tanx/2 out of no where :(

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Im so damn rusty at these

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@mukushla is tan x/2 fr the first one?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Use integral by parts to find the integral fr sin^2 x, choose 1 as the first fn and sin^2 x as second

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Then use sin^2 x as the first fn and the log part as the second one and do integral by parts

angela210793
 4 years ago
Best ResponseYou've already chosen the best response.0ur saying to take sin^2x as u??? or as v???dw:1341259515119:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0xsin^2 x  xsin(2x)dx

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0xsin2x again by parts

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0No one else wanna help?

angela210793
 4 years ago
Best ResponseYou've already chosen the best response.0where did u find x(sin2x)???

angela210793
 4 years ago
Best ResponseYou've already chosen the best response.0but isn't (sin^2x)'=2sinxcosx :O

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thats the saME as sin2x

angela210793
 4 years ago
Best ResponseYou've already chosen the best response.0oops right..sorry :S

angela210793
 4 years ago
Best ResponseYou've already chosen the best response.0wht's the integral of ln..i have no idea at all :'(

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0take that as the second fn

angela210793
 4 years ago
Best ResponseYou've already chosen the best response.0Him..I'm sorry...wht's fn????i am not getting it :S

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0second function..this is really complicated

angela210793
 4 years ago
Best ResponseYou've already chosen the best response.0ok ok thanks Him :D

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1341261306954:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1341261417690:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1341261432803:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1341261510260:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1341261611989:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1341261725308:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1341261826367:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1341261923583:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1341262034160:dw

apoorvk
 4 years ago
Best ResponseYou've already chosen the best response.0@mahmit2012 great work, but the second is an indefinite one I believe.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0indefinite integral has no close function solution so for an exam it is impossible. I sure there in an symmetric interval and the answer is zero because the function is odd.

angela210793
 4 years ago
Best ResponseYou've already chosen the best response.0@mahmit2012 ur a genius :D Thanks a lot :D (by the way the second is still undefined) :D
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