## angela210793 Group Title @Everyone that can and wants to help me pass the exam... 2 years ago 2 years ago

1. him1618

Right here for you :)

2. angela210793

|dw:1341258864115:dw|

3. angela210793

Thanks Him :D

4. him1618

this is bad though

5. angela210793

lol...tht's how everything is in my book...

6. angela210793

ok..here's another one|dw:1341259083895:dw|

7. mukushla

let $t=\tan \frac{x}{2}$

8. angela210793

can u go on please...im not good at integrals especially when u get t=tanx/2 out of no where :(

9. him1618

Im so damn rusty at these

10. him1618

@mukushla is tan x/2 fr the first one?

11. him1618

Use integral by parts to find the integral fr sin^2 x, choose 1 as the first fn and sin^2 x as second

12. him1618

Then use sin^2 x as the first fn and the log part as the second one and do integral by parts

13. angela210793

ur saying to take sin^2x as u??? or as v???|dw:1341259515119:dw|

14. him1618

sin^2 x as u

15. him1618

xsin^2 x - xsin(2x)dx

16. him1618

xsin2x again by parts

17. him1618

No one else wanna help?

18. angela210793

where did u find x(sin2x)???

19. him1618

in u'vdx dx

20. him1618

@dpaInc help

21. angela210793

but isn't (sin^2x)'=2sinxcosx :O

22. him1618

thats the saME as sin2x

23. angela210793

to find du i mean

24. angela210793

oops right..sorry :S

25. angela210793

wht's the integral of ln..i have no idea at all :'(

26. him1618

take that as the second fn

27. angela210793

Him..I'm sorry...wht's fn????i am not getting it :S

28. him1618

second function..this is really complicated

29. angela210793

ok ok thanks Him :D

30. mahmit2012

|dw:1341261306954:dw|

31. mahmit2012

|dw:1341261417690:dw|

32. mahmit2012

|dw:1341261432803:dw|

33. mahmit2012

|dw:1341261510260:dw|

34. mahmit2012

|dw:1341261611989:dw|

35. mahmit2012

|dw:1341261725308:dw|

36. mahmit2012

|dw:1341261826367:dw|

37. mahmit2012

|dw:1341261923583:dw|

38. mahmit2012

|dw:1341262034160:dw|

39. apoorvk

@mahmit2012 great work, but the second is an indefinite one I believe.

40. mahmit2012

indefinite integral has no close function solution so for an exam it is impossible. I sure there in an symmetric interval and the answer is zero because the function is odd.

41. angela210793

@mahmit2012 ur a genius :D Thanks a lot :D (by the way the second is still undefined) :D