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angela210793

@Everyone that can and wants to help me pass the exam...

  • one year ago
  • one year ago

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  1. him1618
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    Right here for you :)

    • one year ago
  2. angela210793
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    |dw:1341258864115:dw|

    • one year ago
  3. angela210793
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    Thanks Him :D

    • one year ago
  4. him1618
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    this is bad though

    • one year ago
  5. angela210793
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    lol...tht's how everything is in my book...

    • one year ago
  6. angela210793
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    ok..here's another one|dw:1341259083895:dw|

    • one year ago
  7. mukushla
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    let \[t=\tan \frac{x}{2}\]

    • one year ago
  8. angela210793
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    can u go on please...im not good at integrals especially when u get t=tanx/2 out of no where :(

    • one year ago
  9. him1618
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    Im so damn rusty at these

    • one year ago
  10. him1618
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    @mukushla is tan x/2 fr the first one?

    • one year ago
  11. him1618
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    Use integral by parts to find the integral fr sin^2 x, choose 1 as the first fn and sin^2 x as second

    • one year ago
  12. him1618
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    Then use sin^2 x as the first fn and the log part as the second one and do integral by parts

    • one year ago
  13. angela210793
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    ur saying to take sin^2x as u??? or as v???|dw:1341259515119:dw|

    • one year ago
  14. him1618
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    sin^2 x as u

    • one year ago
  15. him1618
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    xsin^2 x - xsin(2x)dx

    • one year ago
  16. him1618
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    xsin2x again by parts

    • one year ago
  17. him1618
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    No one else wanna help?

    • one year ago
  18. angela210793
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    where did u find x(sin2x)???

    • one year ago
  19. him1618
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    in u'vdx dx

    • one year ago
  20. him1618
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    @dpaInc help

    • one year ago
  21. angela210793
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    but isn't (sin^2x)'=2sinxcosx :O

    • one year ago
  22. him1618
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    thats the saME as sin2x

    • one year ago
  23. angela210793
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    to find du i mean

    • one year ago
  24. angela210793
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    oops right..sorry :S

    • one year ago
  25. angela210793
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    wht's the integral of ln..i have no idea at all :'(

    • one year ago
  26. him1618
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    take that as the second fn

    • one year ago
  27. angela210793
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    Him..I'm sorry...wht's fn????i am not getting it :S

    • one year ago
  28. him1618
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    second function..this is really complicated

    • one year ago
  29. angela210793
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    ok ok thanks Him :D

    • one year ago
  30. mahmit2012
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    |dw:1341261306954:dw|

    • one year ago
  31. mahmit2012
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    |dw:1341261417690:dw|

    • one year ago
  32. mahmit2012
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    |dw:1341261432803:dw|

    • one year ago
  33. mahmit2012
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    |dw:1341261510260:dw|

    • one year ago
  34. mahmit2012
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    |dw:1341261611989:dw|

    • one year ago
  35. mahmit2012
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    |dw:1341261725308:dw|

    • one year ago
  36. mahmit2012
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    |dw:1341261826367:dw|

    • one year ago
  37. mahmit2012
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    |dw:1341261923583:dw|

    • one year ago
  38. mahmit2012
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    |dw:1341262034160:dw|

    • one year ago
  39. apoorvk
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    @mahmit2012 great work, but the second is an indefinite one I believe.

    • one year ago
  40. mahmit2012
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    indefinite integral has no close function solution so for an exam it is impossible. I sure there in an symmetric interval and the answer is zero because the function is odd.

    • one year ago
  41. angela210793
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    @mahmit2012 ur a genius :D Thanks a lot :D (by the way the second is still undefined) :D

    • one year ago
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