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angela210793Best ResponseYou've already chosen the best response.0
dw:1341258864115:dw
 one year ago

angela210793Best ResponseYou've already chosen the best response.0
lol...tht's how everything is in my book...
 one year ago

angela210793Best ResponseYou've already chosen the best response.0
ok..here's another onedw:1341259083895:dw
 one year ago

mukushlaBest ResponseYou've already chosen the best response.0
let \[t=\tan \frac{x}{2}\]
 one year ago

angela210793Best ResponseYou've already chosen the best response.0
can u go on please...im not good at integrals especially when u get t=tanx/2 out of no where :(
 one year ago

him1618Best ResponseYou've already chosen the best response.0
Im so damn rusty at these
 one year ago

him1618Best ResponseYou've already chosen the best response.0
@mukushla is tan x/2 fr the first one?
 one year ago

him1618Best ResponseYou've already chosen the best response.0
Use integral by parts to find the integral fr sin^2 x, choose 1 as the first fn and sin^2 x as second
 one year ago

him1618Best ResponseYou've already chosen the best response.0
Then use sin^2 x as the first fn and the log part as the second one and do integral by parts
 one year ago

angela210793Best ResponseYou've already chosen the best response.0
ur saying to take sin^2x as u??? or as v???dw:1341259515119:dw
 one year ago

him1618Best ResponseYou've already chosen the best response.0
No one else wanna help?
 one year ago

angela210793Best ResponseYou've already chosen the best response.0
where did u find x(sin2x)???
 one year ago

angela210793Best ResponseYou've already chosen the best response.0
but isn't (sin^2x)'=2sinxcosx :O
 one year ago

him1618Best ResponseYou've already chosen the best response.0
thats the saME as sin2x
 one year ago

angela210793Best ResponseYou've already chosen the best response.0
to find du i mean
 one year ago

angela210793Best ResponseYou've already chosen the best response.0
oops right..sorry :S
 one year ago

angela210793Best ResponseYou've already chosen the best response.0
wht's the integral of ln..i have no idea at all :'(
 one year ago

him1618Best ResponseYou've already chosen the best response.0
take that as the second fn
 one year ago

angela210793Best ResponseYou've already chosen the best response.0
Him..I'm sorry...wht's fn????i am not getting it :S
 one year ago

him1618Best ResponseYou've already chosen the best response.0
second function..this is really complicated
 one year ago

angela210793Best ResponseYou've already chosen the best response.0
ok ok thanks Him :D
 one year ago

mahmit2012Best ResponseYou've already chosen the best response.2
dw:1341261306954:dw
 one year ago

mahmit2012Best ResponseYou've already chosen the best response.2
dw:1341261417690:dw
 one year ago

mahmit2012Best ResponseYou've already chosen the best response.2
dw:1341261432803:dw
 one year ago

mahmit2012Best ResponseYou've already chosen the best response.2
dw:1341261510260:dw
 one year ago

mahmit2012Best ResponseYou've already chosen the best response.2
dw:1341261611989:dw
 one year ago

mahmit2012Best ResponseYou've already chosen the best response.2
dw:1341261725308:dw
 one year ago

mahmit2012Best ResponseYou've already chosen the best response.2
dw:1341261826367:dw
 one year ago

mahmit2012Best ResponseYou've already chosen the best response.2
dw:1341261923583:dw
 one year ago

mahmit2012Best ResponseYou've already chosen the best response.2
dw:1341262034160:dw
 one year ago

apoorvkBest ResponseYou've already chosen the best response.0
@mahmit2012 great work, but the second is an indefinite one I believe.
 one year ago

mahmit2012Best ResponseYou've already chosen the best response.2
indefinite integral has no close function solution so for an exam it is impossible. I sure there in an symmetric interval and the answer is zero because the function is odd.
 one year ago

angela210793Best ResponseYou've already chosen the best response.0
@mahmit2012 ur a genius :D Thanks a lot :D (by the way the second is still undefined) :D
 one year ago
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