angela210793
@Everyone that can and wants to help me pass the exam...
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him1618
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Right here for you :)
angela210793
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|dw:1341258864115:dw|
angela210793
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Thanks Him :D
him1618
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this is bad though
angela210793
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lol...tht's how everything is in my book...
angela210793
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ok..here's another one|dw:1341259083895:dw|
mukushla
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let
\[t=\tan \frac{x}{2}\]
angela210793
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can u go on please...im not good at integrals especially when u get t=tanx/2 out of no where :(
him1618
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Im so damn rusty at these
him1618
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@mukushla is tan x/2 fr the first one?
him1618
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Use integral by parts to find the integral fr sin^2 x, choose 1 as the first fn and sin^2 x as second
him1618
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Then use sin^2 x as the first fn and the log part as the second one and do integral by parts
angela210793
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ur saying to take sin^2x as u??? or as v???|dw:1341259515119:dw|
him1618
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sin^2 x as u
him1618
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xsin^2 x - xsin(2x)dx
him1618
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xsin2x again by parts
him1618
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No one else wanna help?
angela210793
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where did u find x(sin2x)???
him1618
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in u'vdx dx
him1618
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@dpaInc help
angela210793
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but isn't (sin^2x)'=2sinxcosx :O
him1618
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thats the saME as sin2x
angela210793
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to find du i mean
angela210793
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oops right..sorry :S
angela210793
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wht's the integral of ln..i have no idea at all :'(
him1618
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take that as the second fn
angela210793
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Him..I'm sorry...wht's fn????i am not getting it :S
him1618
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second function..this is really complicated
angela210793
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ok ok thanks Him :D
mahmit2012
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mahmit2012
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mahmit2012
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mahmit2012
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mahmit2012
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mahmit2012
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mahmit2012
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mahmit2012
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mahmit2012
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apoorvk
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@mahmit2012 great work, but the second is an indefinite one I believe.
mahmit2012
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indefinite integral has no close function solution so for an exam it is impossible.
I sure there in an symmetric interval and the answer is zero because the function is odd.
angela210793
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@mahmit2012 ur a genius :D Thanks a lot :D
(by the way the second is still undefined) :D