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Right here for you :)
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Thanks Him :D

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Other answers:

this is bad though
lol...tht's how everything is in my book...
ok..here's another one|dw:1341259083895:dw|
let \[t=\tan \frac{x}{2}\]
can u go on please...im not good at integrals especially when u get t=tanx/2 out of no where :(
Im so damn rusty at these
@mukushla is tan x/2 fr the first one?
Use integral by parts to find the integral fr sin^2 x, choose 1 as the first fn and sin^2 x as second
Then use sin^2 x as the first fn and the log part as the second one and do integral by parts
ur saying to take sin^2x as u??? or as v???|dw:1341259515119:dw|
sin^2 x as u
xsin^2 x - xsin(2x)dx
xsin2x again by parts
No one else wanna help?
where did u find x(sin2x)???
in u'vdx dx
@dpaInc help
but isn't (sin^2x)'=2sinxcosx :O
thats the saME as sin2x
to find du i mean
oops right..sorry :S
wht's the integral of ln..i have no idea at all :'(
take that as the second fn
Him..I'm sorry...wht's fn????i am not getting it :S
second function..this is really complicated
ok ok thanks Him :D
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@mahmit2012 great work, but the second is an indefinite one I believe.
indefinite integral has no close function solution so for an exam it is impossible. I sure there in an symmetric interval and the answer is zero because the function is odd.
@mahmit2012 ur a genius :D Thanks a lot :D (by the way the second is still undefined) :D

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