A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
can anyone help me to the answer for this... (will post equation in a sec...)
anonymous
 4 years ago
can anyone help me to the answer for this... (will post equation in a sec...)

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{\sqrt{x2}+x}=2\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0root(x2) + x =4 root(x2) = 4x square again

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0x2 = 16  8x + x^2 9x = 18 + x^2 x^2  9x + 18 = 0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(x6)(x3)=0 x=6 or x=3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@niravshah08 how on earth did you get the first line x2 = 16  8x + x^2 ???

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1341261837727:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay i understand.... but is it wrong if i do this.....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1341262013434:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and if it is wrong please explain why

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but there cant be two different ways of doing it... i think yours is right... hmm

slaaibak
 4 years ago
Best ResponseYou've already chosen the best response.1Michelle, your method is wrong, because: \[(a + b)^2 \neq a^2 + b^2\]

slaaibak
 4 years ago
Best ResponseYou've already chosen the best response.1So, when squaring an equation, you literally put the whole LHS and RHS in huge brackets and square the whole bracket

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so what your saying is that i can do this:

slaaibak
 4 years ago
Best ResponseYou've already chosen the best response.1Also, at the end, always check your answers, because (usually when there's a square root) sometimes they yield a negative number under the square root, so the answer is not real

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1341262893119:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah when i did it my method i got a random answer but did notice the  :) just my method is wrong LOL

slaaibak
 4 years ago
Best ResponseYou've already chosen the best response.1Yeah that's correct. Although, it would be easier to, before you square it, take the x over to the other side. It just makes it easier to solve.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ah yeah i see i just tried it and it is possible but just involves alot of roots... and i dont like roots... they scare me... D': thanks for the explanation :D lifesaver :)

slaaibak
 4 years ago
Best ResponseYou've already chosen the best response.1haha yeah, it gets a bit messy.. it's a pleasure :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.