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can anyone help me to the answer for this... (will post equation in a sec...)
 one year ago
 one year ago
can anyone help me to the answer for this... (will post equation in a sec...)
 one year ago
 one year ago

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michelle1503Best ResponseYou've already chosen the best response.0
\[\sqrt{\sqrt{x2}+x}=2\]
 one year ago

him1618Best ResponseYou've already chosen the best response.0
root(x2) + x =4 root(x2) = 4x square again
 one year ago

niravshah08Best ResponseYou've already chosen the best response.0
x2 = 16  8x + x^2 9x = 18 + x^2 x^2  9x + 18 = 0
 one year ago

niravshah08Best ResponseYou've already chosen the best response.0
(x6)(x3)=0 x=6 or x=3
 one year ago

michelle1503Best ResponseYou've already chosen the best response.0
@niravshah08 how on earth did you get the first line x2 = 16  8x + x^2 ???
 one year ago

niravshah08Best ResponseYou've already chosen the best response.0
dw:1341261837727:dw
 one year ago

michelle1503Best ResponseYou've already chosen the best response.0
okay i understand.... but is it wrong if i do this.....
 one year ago

michelle1503Best ResponseYou've already chosen the best response.0
dw:1341262013434:dw
 one year ago

michelle1503Best ResponseYou've already chosen the best response.0
and if it is wrong please explain why
 one year ago

michelle1503Best ResponseYou've already chosen the best response.0
but there cant be two different ways of doing it... i think yours is right... hmm
 one year ago

slaaibakBest ResponseYou've already chosen the best response.1
Michelle, your method is wrong, because: \[(a + b)^2 \neq a^2 + b^2\]
 one year ago

slaaibakBest ResponseYou've already chosen the best response.1
So, when squaring an equation, you literally put the whole LHS and RHS in huge brackets and square the whole bracket
 one year ago

michelle1503Best ResponseYou've already chosen the best response.0
so what your saying is that i can do this:
 one year ago

slaaibakBest ResponseYou've already chosen the best response.1
Also, at the end, always check your answers, because (usually when there's a square root) sometimes they yield a negative number under the square root, so the answer is not real
 one year ago

michelle1503Best ResponseYou've already chosen the best response.0
dw:1341262893119:dw
 one year ago

michelle1503Best ResponseYou've already chosen the best response.0
yeah when i did it my method i got a random answer but did notice the  :) just my method is wrong LOL
 one year ago

slaaibakBest ResponseYou've already chosen the best response.1
Yeah that's correct. Although, it would be easier to, before you square it, take the x over to the other side. It just makes it easier to solve.
 one year ago

michelle1503Best ResponseYou've already chosen the best response.0
ah yeah i see i just tried it and it is possible but just involves alot of roots... and i dont like roots... they scare me... D': thanks for the explanation :D lifesaver :)
 one year ago

slaaibakBest ResponseYou've already chosen the best response.1
haha yeah, it gets a bit messy.. it's a pleasure :)
 one year ago
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