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anonymous
 3 years ago
can anyone help me to the answer for this... (will post equation in a sec...)
anonymous
 3 years ago
can anyone help me to the answer for this... (will post equation in a sec...)

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{\sqrt{x2}+x}=2\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0root(x2) + x =4 root(x2) = 4x square again

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0x2 = 16  8x + x^2 9x = 18 + x^2 x^2  9x + 18 = 0

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0(x6)(x3)=0 x=6 or x=3

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@niravshah08 how on earth did you get the first line x2 = 16  8x + x^2 ???

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1341261837727:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay i understand.... but is it wrong if i do this.....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1341262013434:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and if it is wrong please explain why

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but there cant be two different ways of doing it... i think yours is right... hmm

slaaibak
 3 years ago
Best ResponseYou've already chosen the best response.1Michelle, your method is wrong, because: \[(a + b)^2 \neq a^2 + b^2\]

slaaibak
 3 years ago
Best ResponseYou've already chosen the best response.1So, when squaring an equation, you literally put the whole LHS and RHS in huge brackets and square the whole bracket

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so what your saying is that i can do this:

slaaibak
 3 years ago
Best ResponseYou've already chosen the best response.1Also, at the end, always check your answers, because (usually when there's a square root) sometimes they yield a negative number under the square root, so the answer is not real

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1341262893119:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yeah when i did it my method i got a random answer but did notice the  :) just my method is wrong LOL

slaaibak
 3 years ago
Best ResponseYou've already chosen the best response.1Yeah that's correct. Although, it would be easier to, before you square it, take the x over to the other side. It just makes it easier to solve.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ah yeah i see i just tried it and it is possible but just involves alot of roots... and i dont like roots... they scare me... D': thanks for the explanation :D lifesaver :)

slaaibak
 3 years ago
Best ResponseYou've already chosen the best response.1haha yeah, it gets a bit messy.. it's a pleasure :)
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