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michelle1503 Group Title

can anyone help me to the answer for this... (will post equation in a sec...)

  • 2 years ago
  • 2 years ago

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  1. michelle1503 Group Title
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    \[\sqrt{\sqrt{x-2}+x}=2\]

    • 2 years ago
  2. him1618 Group Title
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    Square both sides

    • 2 years ago
  3. him1618 Group Title
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    root(x-2) + x =4 root(x-2) = 4-x square again

    • 2 years ago
  4. niravshah08 Group Title
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    x-2 = 16 - 8x + x^2 9x = 18 + x^2 x^2 - 9x + 18 = 0

    • 2 years ago
  5. niravshah08 Group Title
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    (x-6)(x-3)=0 x=6 or x=3

    • 2 years ago
  6. michelle1503 Group Title
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    @niravshah08 how on earth did you get the first line x-2 = 16 - 8x + x^2 ???

    • 2 years ago
  7. niravshah08 Group Title
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    |dw:1341261837727:dw|

    • 2 years ago
  8. michelle1503 Group Title
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    okay i understand.... but is it wrong if i do this.....

    • 2 years ago
  9. michelle1503 Group Title
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    |dw:1341262013434:dw|

    • 2 years ago
  10. michelle1503 Group Title
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    and if it is wrong please explain why

    • 2 years ago
  11. michelle1503 Group Title
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    but there cant be two different ways of doing it... i think yours is right... hmm

    • 2 years ago
  12. slaaibak Group Title
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    Michelle, your method is wrong, because: \[(a + b)^2 \neq a^2 + b^2\]

    • 2 years ago
  13. slaaibak Group Title
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    So, when squaring an equation, you literally put the whole LHS and RHS in huge brackets and square the whole bracket

    • 2 years ago
  14. michelle1503 Group Title
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    so what your saying is that i can do this:

    • 2 years ago
  15. slaaibak Group Title
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    Also, at the end, always check your answers, because (usually when there's a square root) sometimes they yield a negative number under the square root, so the answer is not real

    • 2 years ago
  16. michelle1503 Group Title
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    |dw:1341262893119:dw|

    • 2 years ago
  17. michelle1503 Group Title
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    yeah when i did it my method i got a random answer but did notice the - :) just my method is wrong LOL

    • 2 years ago
  18. slaaibak Group Title
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    Yeah that's correct. Although, it would be easier to, before you square it, take the x over to the other side. It just makes it easier to solve.

    • 2 years ago
  19. michelle1503 Group Title
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    ah yeah i see i just tried it and it is possible but just involves alot of roots... and i dont like roots... they scare me... D': thanks for the explanation :D lifesaver :)

    • 2 years ago
  20. slaaibak Group Title
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    haha yeah, it gets a bit messy.. it's a pleasure :)

    • 2 years ago
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