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MathSofiya
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\[\int_{0}^{1} \frac{1}{1+\sqrt[3]{x} } dx\]
\[u=\sqrt[3]{x}\]
\[du=\frac 1 3 \frac{1}{\sqrt[3]{x^2}}dx\]
\[3du=\frac{1}{\sqrt[3]{x^2}}dx\]
\[3\sqrt[3]{x^2}du=dx\]
\[3u^2du=dx \*\possible\error\]
\[\int_{0}^{1} \frac{3u^2}{1+u } du\]
\[3\int_{0}^{1} \frac{u^2}{1+u } du\]
long division
\[u1+\frac{1}{u+1}\]
\[3\int_{0}^{1} udu3\int_{0}^{1} 1du+3\int_{0}^{1} \frac{1}{u+1}du\]
something is missing...
<looking sideways :\ >
 2 years ago
 2 years ago
MathSofiya Group Title
\[\int_{0}^{1} \frac{1}{1+\sqrt[3]{x} } dx\] \[u=\sqrt[3]{x}\] \[du=\frac 1 3 \frac{1}{\sqrt[3]{x^2}}dx\] \[3du=\frac{1}{\sqrt[3]{x^2}}dx\] \[3\sqrt[3]{x^2}du=dx\] \[3u^2du=dx \*\possible\error\] \[\int_{0}^{1} \frac{3u^2}{1+u } du\] \[3\int_{0}^{1} \frac{u^2}{1+u } du\] long division \[u1+\frac{1}{u+1}\] \[3\int_{0}^{1} udu3\int_{0}^{1} 1du+3\int_{0}^{1} \frac{1}{u+1}du\] something is missing... <looking sideways :\ >
 2 years ago
 2 years ago

This Question is Closed

MathSofiya Group TitleBest ResponseYou've already chosen the best response.1
where did the crowd go? Come back....!!!!!
 2 years ago

Thomas9 Group TitleBest ResponseYou've already chosen the best response.0
I'm not very good at these I'm afraid.
 2 years ago

MathSofiya Group TitleBest ResponseYou've already chosen the best response.1
yes you are! believe in yourself!1 We'll work through this together
 2 years ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.1
busy reading through it now.. how do you know you are wrong btw?
 2 years ago

MathSofiya Group TitleBest ResponseYou've already chosen the best response.1
well...I simply slapped a 2 over the u. But It didn't seem to belong there since it was originally under the radicant
 2 years ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.1
it's correct. Also, not sure what you mean by "slapped a 2 over the u" haha
 2 years ago

MathSofiya Group TitleBest ResponseYou've already chosen the best response.1
i throw my numbers around...ok well, what about the long division?
 2 years ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.1
also correct
 2 years ago

MathSofiya Group TitleBest ResponseYou've already chosen the best response.1
silly question, what do I have to do to mathematically check that....what do I multiply it to? I know, silly question....
 2 years ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.1
you just add it up
 2 years ago

MathSofiya Group TitleBest ResponseYou've already chosen the best response.1
<looking sideways>
 2 years ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.1
should give you the same thing you started with
 2 years ago

MathSofiya Group TitleBest ResponseYou've already chosen the best response.1
aaahhhhh...got it! create a common denominator and add
 2 years ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.1
haha yeah, that's it. sorry, I'm not very clear haha
 2 years ago

MathSofiya Group TitleBest ResponseYou've already chosen the best response.1
thank you @slaaibak
 2 years ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.1
glad to help, although you mastered it yourself :)
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.0
yep... i don't see anything wrong...
 2 years ago

MathSofiya Group TitleBest ResponseYou've already chosen the best response.1
Thanks everyone! Just needed the reassurance. I don't trust my own book keeping
 2 years ago
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