Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

\[\int_{0}^{1} \frac{1}{1+\sqrt[3]{x} } dx\] \[u=\sqrt[3]{x}\] \[du=\frac 1 3 \frac{1}{\sqrt[3]{x^2}}dx\] \[3du=\frac{1}{\sqrt[3]{x^2}}dx\] \[3\sqrt[3]{x^2}du=dx\] \[3u^2du=dx \*\possible\error\] \[\int_{0}^{1} \frac{3u^2}{1+u } du\] \[3\int_{0}^{1} \frac{u^2}{1+u } du\] long division \[u-1+\frac{1}{u+1}\] \[3\int_{0}^{1} udu-3\int_{0}^{1} 1du+3\int_{0}^{1} \frac{1}{u+1}du\] something is missing...

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the expert answer you'll need to create a free account at Brainly

where did the crowd go? Come back....!!!!!
I'm not very good at these I'm afraid.
yes you are! believe in yourself!1 We'll work through this together

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

busy reading through it now.. how do you know you are wrong btw?
well...I simply slapped a 2 over the u. But It didn't seem to belong there since it was originally under the radicant
it's correct. Also, not sure what you mean by "slapped a 2 over the u" haha
i throw my numbers around...ok well, what about the long division?
also correct
silly question, what do I have to do to mathematically check that....what do I multiply it to? I know, silly question....
you just add it up
should give you the same thing you started with
aaahhhhh...got it! create a common denominator and add
haha yeah, that's it. sorry, I'm not very clear haha
thank you @slaaibak
glad to help, although you mastered it yourself :)
yep... i don't see anything wrong...
Thanks everyone! Just needed the reassurance. I don't trust my own book keeping

Not the answer you are looking for?

Search for more explanations.

Ask your own question