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chadandtricia_2009 Group Title

What is the factored form of the expression? k2 – 9h2 A. (k + 3h)(k + 3h) B. h2(k + 3)(k – 3) C. (k + 3h)(k – 3h) D. (k – 3h2)(k + 3)

  • 2 years ago
  • 2 years ago

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  1. doubledrive Group Title
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    A

    • 2 years ago
  2. chadandtricia_2009 Group Title
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    can you show me how you got that please?

    • 2 years ago
  3. zeesbrat3 Group Title
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    A

    • 2 years ago
  4. doubledrive Group Title
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    Nevermind, C

    • 2 years ago
  5. chadandtricia_2009 Group Title
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    i don't understand how to do it

    • 2 years ago
  6. doubledrive Group Title
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    K*K=K2 +3*-3=-9 H*H=H2

    • 2 years ago
  7. Calcmathlete Group Title
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    It is C. You have to first recognize the fact that this is a difference in squares pattern. \[a^{2} - b^{2} = (a + b)(a - b)\]

    • 2 years ago
  8. doubledrive Group Title
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    Which becomes k2-9h2

    • 2 years ago
  9. Calcmathlete Group Title
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    If you want to factor it without the pattern, then find factors of -9 that add up to 0. These factors are -3 and 3. THerefore, (k + 3h)(k – 3h)

    • 2 years ago
  10. zeesbrat3 Group Title
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    In this problem you are dealing with perfect squares, so it was easier just to square root them. However, that only works if all of them are actually perfect squares. If you don't know what a perfect square is, it is a number multiplied by itself.

    • 2 years ago
  11. chadandtricia_2009 Group Title
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    so what do I plug into the pattern?

    • 2 years ago
  12. Calcmathlete Group Title
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    a = k b = 3h See how k is squared and 3h is squared as well? k^2 = k^2 3^2h^2 = 9h^2

    • 2 years ago
  13. zeesbrat3 Group Title
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    \[K timesK =K ^{2} 3h\times3h=9h /sqrt{9}=3\]

    • 2 years ago
  14. zeesbrat3 Group Title
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    sorry, it didnt space out like I planned..

    • 2 years ago
  15. chadandtricia_2009 Group Title
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    ok got it now.

    • 2 years ago
  16. chadandtricia_2009 Group Title
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    thanks alot all of you

    • 2 years ago
  17. myininaya Group Title
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    @zeesbrat3 and @doubledrive In the future, please don't just give the answer (sometimes people just want to cheat and that is not what OpenStudy is about.) Please guide the user so that the person can come to the answer themselves. Also @chadandtricia_2009 thanks for asking for an explanation. :)

    • 2 years ago
  18. myininaya Group Title
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    And that message goes to anyone I miss that didn't know the new CoC. thanks.

    • 2 years ago
  19. doubledrive Group Title
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    @myininaya for your information, i answered the question and i explained it.

    • 2 years ago
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