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chadandtricia_2009
 2 years ago
What is the factored form of the expression?
k2 – 9h2
A. (k + 3h)(k + 3h)
B. h2(k + 3)(k – 3)
C. (k + 3h)(k – 3h)
D. (k – 3h2)(k + 3)
chadandtricia_2009
 2 years ago
What is the factored form of the expression? k2 – 9h2 A. (k + 3h)(k + 3h) B. h2(k + 3)(k – 3) C. (k + 3h)(k – 3h) D. (k – 3h2)(k + 3)

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chadandtricia_2009
 2 years ago
Best ResponseYou've already chosen the best response.1can you show me how you got that please?

chadandtricia_2009
 2 years ago
Best ResponseYou've already chosen the best response.1i don't understand how to do it

doubledrive
 2 years ago
Best ResponseYou've already chosen the best response.0K*K=K2 +3*3=9 H*H=H2

Calcmathlete
 2 years ago
Best ResponseYou've already chosen the best response.2It is C. You have to first recognize the fact that this is a difference in squares pattern. \[a^{2}  b^{2} = (a + b)(a  b)\]

doubledrive
 2 years ago
Best ResponseYou've already chosen the best response.0Which becomes k29h2

Calcmathlete
 2 years ago
Best ResponseYou've already chosen the best response.2If you want to factor it without the pattern, then find factors of 9 that add up to 0. These factors are 3 and 3. THerefore, (k + 3h)(k – 3h)

zeesbrat3
 2 years ago
Best ResponseYou've already chosen the best response.0In this problem you are dealing with perfect squares, so it was easier just to square root them. However, that only works if all of them are actually perfect squares. If you don't know what a perfect square is, it is a number multiplied by itself.

chadandtricia_2009
 2 years ago
Best ResponseYou've already chosen the best response.1so what do I plug into the pattern?

Calcmathlete
 2 years ago
Best ResponseYou've already chosen the best response.2a = k b = 3h See how k is squared and 3h is squared as well? k^2 = k^2 3^2h^2 = 9h^2

zeesbrat3
 2 years ago
Best ResponseYou've already chosen the best response.0\[K timesK =K ^{2} 3h\times3h=9h /sqrt{9}=3\]

zeesbrat3
 2 years ago
Best ResponseYou've already chosen the best response.0sorry, it didnt space out like I planned..

chadandtricia_2009
 2 years ago
Best ResponseYou've already chosen the best response.1ok got it now.

chadandtricia_2009
 2 years ago
Best ResponseYou've already chosen the best response.1thanks alot all of you

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.0@zeesbrat3 and @doubledrive In the future, please don't just give the answer (sometimes people just want to cheat and that is not what OpenStudy is about.) Please guide the user so that the person can come to the answer themselves. Also @chadandtricia_2009 thanks for asking for an explanation. :)

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.0And that message goes to anyone I miss that didn't know the new CoC. thanks.

doubledrive
 2 years ago
Best ResponseYou've already chosen the best response.0@myininaya for your information, i answered the question and i explained it.
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