Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Boushra Group Title

The following diagram demonstrates an elastic collision between two balls of equal masses. The black ball is at rest and the final velocity v1 of the white ball = 3 m/s Find: 1. the initial velocity of the white ball, 2. the velocity of the black ball after the collision 3. the angle (theta) 4. the change in the kinetic energy Is there a possibility we can discuss everything here? I'm having a hard time understanding. please help!

  • 2 years ago
  • 2 years ago

  • This Question is Closed
  1. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    We should use the perfect inelastic collision equation m1u1 + m2u2 = (m1+m2)v

    • 2 years ago
  2. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    can u post the diagram as well?

    • 2 years ago
  3. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    yep just a sec

    • 2 years ago
  4. meera_yadav Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    hii, is the black bal at rest after the collision? if yes then white ball's initial velocity is zero just before collision

    • 2 years ago
  5. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1341315928417:dw|

    • 2 years ago
  6. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    the black ball is in motion after collision

    • 2 years ago
  7. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    then first of all, we can't use the eq u posted abv since the 2 bodies are not sticking together after collision.

    • 2 years ago
  8. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    oh... yeah right @Vaidehi09

    • 2 years ago
  9. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    should we use m1u1+m2u2 = m1v1 + m2v2 ??

    • 2 years ago
  10. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    m1 = m2 = m

    • 2 years ago
  11. meera_yadav Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1341316215450:dw|

    • 2 years ago
  12. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    should we write an equation based on components?

    • 2 years ago
  13. meera_yadav Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    since this is an elastic collision then we must have momentum before collision = momentum after collision !! we must also have change in kinetic energy energy should be zero as there's no external force acting..

    • 2 years ago
  14. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    yes understood :) then

    • 2 years ago
  15. meera_yadav Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    yep ! we should write moemtum shold be resolved.. i.e. horizontal momentum before collison = horizontal momentum after collision same goes for vertical momentum

    • 2 years ago
  16. meera_yadav Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    similar equation we can write it for vertical momentum also !

    • 2 years ago
  17. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    so the first one you drew above is for the horizontal momentum?

    • 2 years ago
  18. meera_yadav Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1341316752653:dw|

    • 2 years ago
  19. meera_yadav Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    yep ! it's for horizontal... 2nd draw is for vertical momentum..

    • 2 years ago
  20. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    @meera_yadav ur first drawing....shouldn't we have vcos(theta) there...instead of sine?

    • 2 years ago
  21. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    for the first drawing: why did you write down sin theta v, shouldn't it be cos theta v? since we're talking about the horizontal? @meera_yadav

    • 2 years ago
  22. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    the eq for horizontal should be u1 = 3cos45 + vcosA

    • 2 years ago
  23. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    supposing theta = A

    • 2 years ago
  24. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    yes, that's what I got @Vaidehi09

    • 2 years ago
  25. meera_yadav Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah! sorry ! that's a mistake ... thanks for pointing out :) plz correct it to cos theta

    • 2 years ago
  26. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    great!!! now we can move on to 2nd equation:

    • 2 years ago
  27. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    .5 mu (squared) = .5 m 3(squared) + .5 m v(squared) <--- why did we use this?

    • 2 years ago
  28. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    wait a sec, but we haven't yet found the value of u1.

    • 2 years ago
  29. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    thats the eq for conservation of KE

    • 2 years ago
  30. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    yeah, I know,... should we label it as eq 2?

    • 2 years ago
  31. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    for KE, i got the eq as (u1)^2 = 3^2 + v^2

    • 2 years ago
  32. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    I think the v in it should be v subscript x, correct?

    • 2 years ago
  33. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    i don't think so. for KE, we don't need components since it is a scalar.

    • 2 years ago
  34. meera_yadav Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    no there's no need for the subscript vaidelhi , because K.E is a scalar quantity...

    • 2 years ago
  35. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    ok, great, I'm following.. so what do we need next.

    • 2 years ago
  36. meera_yadav Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    I think everythings known to u know !!

    • 2 years ago
  37. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    we have another eq, using vertical components for momentum. and that is, vsin theta = 3sin45

    • 2 years ago
  38. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    ok, hold on a sec

    • 2 years ago
  39. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    shouldn't it be 3 sin 45 = - v sin theta?

    • 2 years ago
  40. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    we have it as: 0 = m(3 sin 45) + m (v sin theta) before right?

    • 2 years ago
  41. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    nope. both the vertical components of velocities are in opp direcs. so we get, 0 = 3sin45 - vcosA

    • 2 years ago
  42. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    u mean v sin A ??

    • 2 years ago
  43. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    ah yes....that should be sine

    • 2 years ago
  44. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    so all I need to do is substitute now? with the 3 eq that I've got?

    • 2 years ago
  45. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    yup...try it out. m also doing the same.

    • 2 years ago
  46. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    ok, I'll put my answers down.. let's do that :)

    • 2 years ago
  47. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    do we substitue eq 3 into 1?

    • 2 years ago
  48. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    we need to solve for u1 first, right?

    • 2 years ago
  49. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    i don't know ur numbering. here our the 3 eqs: 1) u = 3cos45 + vcosA 2) u^2 = 9+ v^2 3) vsinA = 3 sin45

    • 2 years ago
  50. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    our unknowns are u, v, A. start anywhere.

    • 2 years ago
  51. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    let's start with u

    • 2 years ago
  52. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    we should substitute eq 2 into 1?

    • 2 years ago
  53. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    yea, u can do that or vice versa. whichever is convenient to u.

    • 2 years ago
  54. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    and the take the square root of it first?

    • 2 years ago
  55. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    that way u can get rid of u.

    • 2 years ago
  56. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    do we go like this: 3 + v = 3 cos 45 + v cos A ??

    • 2 years ago
  57. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    ?

    • 2 years ago
  58. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    how did u get 3 + v ?

    • 2 years ago
  59. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    u^2 = 9 + v^2

    • 2 years ago
  60. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    I took the square root of that

    • 2 years ago
  61. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    u need sqrt( 9+v^2 )

    • 2 years ago
  62. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    no wait....sqrt( a^2 + b^2) is NOT = a + b

    • 2 years ago
  63. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    oh.

    • 2 years ago
  64. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    can you tell me the way you'd solve for the unknowns from the 3 eq we've got, step by step?

    • 2 years ago
  65. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    before that, let me confirm something. is the angle theta = 45 ?

    • 2 years ago
  66. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    no, there are two angles, one is theta and one is 45. different from one another. you can refer back to the diagram above

    • 2 years ago
  67. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    no i mean, do u have the answers?

    • 2 years ago
  68. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    oh yes, it's correct

    • 2 years ago
  69. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    theta = 45

    • 2 years ago
  70. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    great...so i'm on the right path. ok proceed this way...

    • 2 years ago
  71. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    I just need to know the steps, I've having a hard time substituting..

    • 2 years ago
  72. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    no prob, i'll help.

    • 2 years ago
  73. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    :)

    • 2 years ago
  74. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    can we start by knowing how to substitute and figure out theta?

    • 2 years ago
  75. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    first, swap ur RHS and LHS of eq 3 and add it to eq 1.

    • 2 years ago
  76. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    what is RHS and LHS?

    • 2 years ago
  77. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    right hand side and left hand side of an eq.

    • 2 years ago
  78. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    ok, I'd swap them and add them to the 1st equation

    • 2 years ago
  79. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    so ur eq 3 becomes: 3sin45 = vsinA

    • 2 years ago
  80. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    right. sow rite down what u got here.

    • 2 years ago
  81. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    ok good

    • 2 years ago
  82. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    so u should have now, u + 3sin45 = 3cos45 + vcosA + vsinA

    • 2 years ago
  83. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    yes! i got that too

    • 2 years ago
  84. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    cancel out 3sin45 and 3cos45. so now u have, u = v( cosA + sinA)

    • 2 years ago
  85. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    is there a trig rule for cancelling them out that i should know of?

    • 2 years ago
  86. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    what is sin45?

    • 2 years ago
  87. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    0.707106 which is the same is cos 45

    • 2 years ago
  88. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    so that's how we cancel them out.. ok!

    • 2 years ago
  89. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    right...so mathematically, those 2 terms are exactly the same. and on opp sides of the = sign. so we can cancel them out.

    • 2 years ago
  90. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    ok, moving on...substitute that eq in eq2.

    • 2 years ago
  91. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    perfect, now we're left with u = v ( cos A + sin A)

    • 2 years ago
  92. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    u should get : v^2(sinA+cosA)^2 = 9+ v^2

    • 2 years ago
  93. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    do we get: (v(cos A + sin A) ^2 = 9 + v^2 ?

    • 2 years ago
  94. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    yep, the same.

    • 2 years ago
  95. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    that's right, now expand LHS and show me what u get.

    • 2 years ago
  96. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    i think there' a rule saying cos A + sin A = 1?

    • 2 years ago
  97. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    no...that's when cosA and sinA both are squared terms

    • 2 years ago
  98. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    ok, then hold a sec

    • 2 years ago
  99. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    should we get v^2cos^2A +sin^2A = 9 + v^2 ??

    • 2 years ago
  100. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    do u know the expansion of (a+b)^2 ?

    • 2 years ago
  101. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    yes... oh wait, I made a mistake.. just a sec

    • 2 years ago
  102. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    v^2 sin^2a + 2sinAcosA + cos^2 a = 9 + v^2

    • 2 years ago
  103. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    thats right, except that, the trigo terms should be inside the bracket and v^2 outside it.

    • 2 years ago
  104. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    ok so : v^2 (sin^2a + 2sinAcosA + cos^2 a) = 9 + v^2

    • 2 years ago
  105. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    and then...

    • 2 years ago
  106. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    right, now sin^2a + cos^2a = 1 so we get v^2( 1 + sin2a) = 9 + v^2 v^2 + v^2sin2a = 9 + v^2 v^2sin2a = 9

    • 2 years ago
  107. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    sin2a = 2sinacosa...thats the sub i made.

    • 2 years ago
  108. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    wiat.. shouldn't we habe v^2 (1 + 2sinAcosA) = 9 + v^2 ??

    • 2 years ago
  109. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    look at the second last post. i showed how I substituted.

    • 2 years ago
  110. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    ok hold on

    • 2 years ago
  111. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    there's a formula : sin2A = 2sinAcosA. i used it.

    • 2 years ago
  112. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    aha... ok, got it.. and now what's next?

    • 2 years ago
  113. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    so the final formula here is v^2 sin2 a = 9

    • 2 years ago
  114. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    now divide the eq which we got hen, by eq 3. so \[v ^{2} \sin2A / vsinA = 9/\3sin45\] so we'll get vsinAcosA/sinA = 9 sqrt(2)/3.......since 3sin45 = 3/sqrt(2)

    • 2 years ago
  115. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    in the eq, the RHS is 9/3sin45

    • 2 years ago
  116. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    ok, the RHS is 9/3 sin 45 = 4.2426 ???

    • 2 years ago
  117. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    don't go on to the final values just yet. it'll only complicate things further.

    • 2 years ago
  118. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    continuing the above eq, we'll gte vcosA = 3 sqrt(2)

    • 2 years ago
  119. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    ok

    • 2 years ago
  120. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    gr8! so now divide this eq with ur eq3

    • 2 years ago
  121. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    u should get vcosA/vsinA = 3 rt(2)/ [3/rt(2)]

    • 2 years ago
  122. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    yes that's what i got

    • 2 years ago
  123. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    which would lead us to cotA = 2 or tanA = 1/2

    • 2 years ago
  124. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    so now u can find A = tan^(-1) [1/2]

    • 2 years ago
  125. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    wait cos a/sina = tan a?

    • 2 years ago
  126. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    no, cosa /sina = cota = 1/tana

    • 2 years ago
  127. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    what's cota?

    • 2 years ago
  128. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    cotA

    • 2 years ago
  129. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    yeah, i mean what's cot?

    • 2 years ago
  130. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    u dont know ur trigo ratios?

    • 2 years ago
  131. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    this is the first time I see cot, I will definitely look up all the ratios after this

    • 2 years ago
  132. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    no wait..before solving such questions, u should go and work on ur math. u've reached mechanics, u ought to have a solid base in math for it.

    • 2 years ago
  133. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    so what do i need to look up in regards to trig in mechanics?

    • 2 years ago
  134. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    trigo ratios are elementary in trigo. u need to know the various relations between them. their values for basic angles. formulae etc etc.

    • 2 years ago
  135. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    and then there will come inverse trigo ratios...something that we were going to use here, to find out theta.

    • 2 years ago
  136. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    alright then, nonetheless... i really really really appreciate your help. I will go look those basics up first, and then perhaps come back and solve the question here. Thank you soooo very much :)

    • 2 years ago
  137. Boushra Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    yeah i know inverse ratios :)

    • 2 years ago
  138. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    cool! and considering how much we've solved here, u should be able to go further without any external help. work hard on math! don't ignore it!

    • 2 years ago
  139. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    @Boushra: I had made a calculation error before. after getting v^2sin2A/vsinA = 9/[3/sqrt(2)] we'll get, 2vcosA = 3 rt(2) therefore, vcosA = 3/rt(2) comparing this with eq3, ie., vsinA = 3/rt(2) we can conclude thata cosA = sinA therefore A = 45

    • 2 years ago
  140. Vaidehi09 Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    so after substituting u'll get v = 3m/s u = 3 rt(2) m/s and A = theta = we already got as 45

    • 2 years ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.