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I need help. I need to write an equation in slope intercept and standard form.
Through (5,8) and perpendicular to y=1/2x+14
 one year ago
 one year ago
I need help. I need to write an equation in slope intercept and standard form. Through (5,8) and perpendicular to y=1/2x+14
 one year ago
 one year ago

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mykoBest ResponseYou've already chosen the best response.0
perpendicular means, has slope 2
 one year ago

mubzzBest ResponseYou've already chosen the best response.0
An equation in slope intercept form is written as y=mx + c where 'm' is the slope and 'c' is the intercept. To write any equation in this form, you need the slope and one pair of points it passes through. Suppose the equation you are given represents line A and you have to find the equation of line B. If line A and libe B are perpendicular to each other, we have the following relation: \[slope of A = 1\div (Slope of B)\] Hence slope of line B will be 2 Next you use the following relation \[(yy _{1}) = m(xx_{1})\] Where y1 and x1 are the points you use. In this case, y1 is 8 and x1 is 5 Plus all these values in the relation above and you get y  (8) = 2 (x [5]) => y +8 = 2(x+5) => y +8 = 2x 10 => y = 2x 18 where 18 is your slope
 one year ago

helpmewithmath2012Best ResponseYou've already chosen the best response.0
so how do i write it in standard form
 one year ago

mubzzBest ResponseYou've already chosen the best response.0
y = 2x 18 This is standard form is often written as Ax + By = C Your standard form equation will be 2x + y = 18
 one year ago

helpmewithmath2012Best ResponseYou've already chosen the best response.0
Thank you so much!
 one year ago
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