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A tank filled with propane gas has a temperature of 275 K and a pressure of 25 atm. What happens to the temperature if the pressure is increased to 100 atm? --------------------- stays the same doubles triples quadruples @Austin_Cochran

Chemistry
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The properties of an ideal gas are summed up in chemistry and physics in this neat equation: PV = kT This is saying that (pressure) multipled by (Volume) = (the constant 'k') times (Temperature) . Without getting into all the units and the details, in order to answer this question we only have to understand that when one side of the equation increases, the other side of the equation has to increase by the same multiplier. Increasing the pressure from 25 ATM to 100 ATM, the left side of the equation (PV) is multiplied by 4. (The volume of the tank 'V' remains constant.) If propane behaves like an ideal gas or close to it, then the right side must also multiply by 4, and the absolute temperature becomes 4 times as great. If the tank is perfectly insulated and none of the heat escapes, then the gas in it rises in temperature from 275 K to 1100 K. Read more: http://wiki.answers.com/Q/A_tank_filled_with_propane_gas_has_a_temperature_of_275_K_and_a_pressure_of_25_ATM_what_happens_to_the_temperature_if_the_pressure_is_increased_to_100_ATM#ixzz1zbyzZ8hN
So... It Quaded..
understand it?

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yeah thanks

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