Assume that 1 car in 8 is defective and will not start. If at different times 5 individuals each randomly select a car to test drive, what is the probability that at least 1 of them selects a car that will not start?
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No, that wasn't the answer. This question is in a section over Bernoulli Trials.
The collective probability of any event cannot exceed 1. At least one of them selects a defected car means that there can be more than one defected cars picked.
probability of at least 1 defective car = 1 - (probability of no defective cars)
For one person's pick, probability of non-defective car = 7/8.
For five different draws, this will be (7/8)^5
=>probability of at least 1 defective car = 1 - ((7/8)^5)
=>probability of at least 1 defective car = 1 - (16807/32768)
=>probability of at least 1 defective car = 1 - 0.5129
=>probability of at least 1 defective car = 0.4871