Assume that 1 car in 8 is defective and will not start. If at different times 5 individuals each randomly select a car to test drive, what is the probability that at least 1 of them selects a car that will not start?

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

Assume that 1 car in 8 is defective and will not start. If at different times 5 individuals each randomly select a car to test drive, what is the probability that at least 1 of them selects a car that will not start?

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

No, that wasn't the answer. This question is in a section over Bernoulli Trials.
The collective probability of any event cannot exceed 1. At least one of them selects a defected car means that there can be more than one defected cars picked. So, probability of at least 1 defective car = 1 - (probability of no defective cars) For one person's pick, probability of non-defective car = 7/8. For five different draws, this will be (7/8)^5 Therefore, =>probability of at least 1 defective car = 1 - ((7/8)^5) =>probability of at least 1 defective car = 1 - (16807/32768) =>probability of at least 1 defective car = 1 - 0.5129 =>probability of at least 1 defective car = 0.4871
Is that the correct answer?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

yes
Mubzz thank you yes!!
I thought it was somewhere along that line but i didnt subtract (7/8)^5 from 1. Thats why i didnt get it thank you again!!

Not the answer you are looking for?

Search for more explanations.

Ask your own question