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Assume that 1 car in 8 is defective and will not start. If at different times 5 individuals each randomly select a car to test drive, what is the probability that at least 1 of them selects a car that will not start?
 one year ago
 one year ago
Assume that 1 car in 8 is defective and will not start. If at different times 5 individuals each randomly select a car to test drive, what is the probability that at least 1 of them selects a car that will not start?
 one year ago
 one year ago

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JonnyBaybeeBest ResponseYou've already chosen the best response.0
No, that wasn't the answer. This question is in a section over Bernoulli Trials.
 one year ago

mubzzBest ResponseYou've already chosen the best response.1
The collective probability of any event cannot exceed 1. At least one of them selects a defected car means that there can be more than one defected cars picked. So, probability of at least 1 defective car = 1  (probability of no defective cars) For one person's pick, probability of nondefective car = 7/8. For five different draws, this will be (7/8)^5 Therefore, =>probability of at least 1 defective car = 1  ((7/8)^5) =>probability of at least 1 defective car = 1  (16807/32768) =>probability of at least 1 defective car = 1  0.5129 =>probability of at least 1 defective car = 0.4871
 one year ago

mubzzBest ResponseYou've already chosen the best response.1
Is that the correct answer?
 one year ago

JonnyBaybeeBest ResponseYou've already chosen the best response.0
Mubzz thank you yes!!
 one year ago

JonnyBaybeeBest ResponseYou've already chosen the best response.0
I thought it was somewhere along that line but i didnt subtract (7/8)^5 from 1. Thats why i didnt get it thank you again!!
 one year ago
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