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guccimayne Group Title Graphing anyone help? 2 years ago 2 years ago

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1. guccimayne

2. mubzz

Part 1) coordinates of point A (-5, -2) coordinates of point B (4 , -1) Distance formula = $\sqrt{(x _{2} - x _{1})^{2} +(y _{2} - y _{1})^{2}}$ So your distance between A and B would be $\sqrt{(-5 - 4)^{2} +(-2 + 1)^{2}}$ => $\sqrt{(-9)^{2} +(-1)^{2}}$ => $\sqrt{81 + 1}$ => $\sqrt{82}$ or 9.05

3. guccimayne

so 9.05 would be the answer and it is already rounded to 2 decmial points?

4. guccimayne

5. guccimayne

need help with tht one too please

6. mubzz

Part 2) Part 1) coordinates of point A ( -11, 4) coordinates of point B ( -8 , 8) Distance formula = $\sqrt{(x _{2} - x _{1})^{2} +(y _{2} - y _{1})^{2}}$ So AB is 5 units ----------------------------------------------------------- coordinates of point C ( 3, 2) coordinates of point D ( 7 , -2) Distance formula = $\sqrt{(x _{2} - x _{1})^{2} +(y _{2} - y _{1})^{2}}$ So CD is 10.7703 ----------------------------------------------------------- Divide length of CD by length of AB 10.7703/5 = 2.15406 rounded to 2 decimal places, this is 2.15 times longer

7. guccimayne

so wait what are the answers for the first two graphs ?

8. mubzz

In order to calculate midpoint, $Midpoint (x , y) = (x _{1} + x _{2})/2 , (y _{1} + y _{2})/2$ Midpoint = (12+ -4)/2 , (-7 + 7)/2 midpoint = (4 , 0)

9. mubzz

sorry there was a typo in the answer for part 2. Part 1) 9.05 part 2) 2.15 part 3) 4 , 0

10. guccimayne

these too please

11. mubzz

give me two mins please :)

12. guccimayne

ight

13. guccimayne

would 1png aswer be (4.5,2) ?

14. mubzz

For 2.png, when you have to calculate the midpoint of TS, Midpoint(x,y)=(x1+x2)/2,(y1+y2)/2 Midpoint = (-6+ 3)/2 , (-4 + 2)/2 midpoint = (-1.5 , -1)

15. mubzz

sorry can't think about how to solve 1.png now. I know how to, can't remember :/