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4everjames

  • 2 years ago

A bag has 4 green marbles, 3 red marbles, and 3 yellow marbles. What is the probability that you pick a red marble, do not replace it, and pick another red marble?

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  1. waterineyes
    • 2 years ago
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    How many red marbles are there @4everjames ?

  2. 4everjames
    • 2 years ago
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    @waterineyes 3

  3. mubzz
    • 2 years ago
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    Similar to last question, just some changes: In the beginning, the probability of a red marble is 3/10 After you've picked the first one and do not replace it, the probability of a red marble is 2/9. So your statement would be: Probability of red and red = Probability of 1st red * probability of 2nd red = (3/10) * (2/9) = 6/90 = 1/15

  4. waterineyes
    • 2 years ago
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    Yes.. And what are total number of marbles that bag has?

  5. 4everjames
    • 2 years ago
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    @waterineyes 10

  6. 4everjames
    • 2 years ago
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    @mubzz thanksz!!!! i get it now thanks to u and @waterineyes

  7. mubzz
    • 2 years ago
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    An easy tip to solve all probability questions: When it says (prob of x) AND (prob of y) you multiply, i.e. (prob of x)*(prob of y) When it says (prob of x) OR (prob of y) you add, i.e. (prob of x)+(prob of y)

  8. 4everjames
    • 2 years ago
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    ok just for review (A bag has 5 red marbles, 6 blue marbles and 4 black marbles. What is the probability of picking a red marble, replacing it, and then picking a black marble?

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