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burhan101

  • 2 years ago

simplify

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  1. burhan101
    • 2 years ago
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    \[(x+1)^{2}/x^2+2x-3 \times x^2-2x+1/x^2+4x+3\]

  2. burhan101
    • 2 years ago
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    |dw:1341370090447:dw|

  3. Calcmathlete
    • 2 years ago
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    \(\huge\text{Is the problem: }\frac{(x + 1)^{2}}{x^{2} + 2x - 3} \times \frac{x^{2} - 2x + 1}{x^{2} + 2x + 3}?\)

  4. burhan101
    • 2 years ago
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    yes, i didnt know how to type it in the equation like that

  5. Calcmathlete
    • 2 years ago
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    You have to use the equation editor with a few extra steps. I assume you know how to factor the three trinomials?

  6. Calcmathlete
    • 2 years ago
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    Do you????

  7. burhan101
    • 2 years ago
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    im not sure

  8. burhan101
    • 2 years ago
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    here's what ive done so far

  9. burhan101
    • 2 years ago
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    can you please tell me if it's somewhat right

  10. Calcmathlete
    • 2 years ago
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    Sure.

  11. burhan101
    • 2 years ago
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    |dw:1341370527396:dw|

  12. burhan101
    • 2 years ago
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    oh that's wrong, i factor right ?

  13. Calcmathlete
    • 2 years ago
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    Um...before you do that, factor the three individual trinomials. Try factoring: \(x^{2} + 2x - 3\).

  14. burhan101
    • 2 years ago
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    \[(x-2)(x+1)\]

  15. burhan101
    • 2 years ago
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    is that right?

  16. Calcmathlete
    • 2 years ago
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    Not quite. What are factors of -3 that add to 2?

  17. burhan101
    • 2 years ago
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    -2,-1

  18. Calcmathlete
    • 2 years ago
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    No. -2 x -1 = 2. Not -3. You did it the opposite way. They should add to 2 and multiply to -3.

  19. burhan101
    • 2 years ago
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    OHH ! okay

  20. burhan101
    • 2 years ago
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    -1,3

  21. Calcmathlete
    • 2 years ago
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    YAY! \(x^{2} + 2x - 3 = (x - 1)(x + 3)\) Now, let's factor \(x^{2} - 2x + 1\)

  22. burhan101
    • 2 years ago
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    -1,-1

  23. burhan101
    • 2 years ago
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    (x-1)(x-1)

  24. Calcmathlete
    • 2 years ago
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    Yup. Now finally, let's factor x^{2} + 4x + 3

  25. burhan101
    • 2 years ago
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    (x+3)(x+1)

  26. burhan101
    • 2 years ago
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    |dw:1341371332480:dw|

  27. burhan101
    • 2 years ago
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    |dw:1341371477936:dw|

  28. Calcmathlete
    • 2 years ago
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    You're getting really good! \(\large\frac{(x + 1)(x + 1)}{(x + 3)(x - 1)} \times \frac{(x - 1)(x - 1)}{(x + 3)(x + 1)} = \frac{\cancel{(x + 1)}(x + 1)}{(x + 3)\cancel{(x - 1)}} \times \frac{\cancel{(x - 1)}(x - 1)}{(x + 3)\cancel{(x + 1)}} = \frac{(x + 1)(x - 1)}{(x + 3)(x + 3)}\)Yup :) You got it!

  29. burhan101
    • 2 years ago
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    Thankyou so much ! :)

  30. burhan101
    • 2 years ago
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    so this is the farthest it ca be simplified right

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