## burhan101 2 years ago simplify

1. burhan101

$(x+1)^{2}/x^2+2x-3 \times x^2-2x+1/x^2+4x+3$

2. burhan101

|dw:1341370090447:dw|

3. Calcmathlete

$$\huge\text{Is the problem: }\frac{(x + 1)^{2}}{x^{2} + 2x - 3} \times \frac{x^{2} - 2x + 1}{x^{2} + 2x + 3}?$$

4. burhan101

yes, i didnt know how to type it in the equation like that

5. Calcmathlete

You have to use the equation editor with a few extra steps. I assume you know how to factor the three trinomials?

6. Calcmathlete

Do you????

7. burhan101

im not sure

8. burhan101

here's what ive done so far

9. burhan101

can you please tell me if it's somewhat right

10. Calcmathlete

Sure.

11. burhan101

|dw:1341370527396:dw|

12. burhan101

oh that's wrong, i factor right ?

13. Calcmathlete

Um...before you do that, factor the three individual trinomials. Try factoring: $$x^{2} + 2x - 3$$.

14. burhan101

$(x-2)(x+1)$

15. burhan101

is that right?

16. Calcmathlete

Not quite. What are factors of -3 that add to 2?

17. burhan101

-2,-1

18. Calcmathlete

No. -2 x -1 = 2. Not -3. You did it the opposite way. They should add to 2 and multiply to -3.

19. burhan101

OHH ! okay

20. burhan101

-1,3

21. Calcmathlete

YAY! $$x^{2} + 2x - 3 = (x - 1)(x + 3)$$ Now, let's factor $$x^{2} - 2x + 1$$

22. burhan101

-1,-1

23. burhan101

(x-1)(x-1)

24. Calcmathlete

Yup. Now finally, let's factor x^{2} + 4x + 3

25. burhan101

(x+3)(x+1)

26. burhan101

|dw:1341371332480:dw|

27. burhan101

|dw:1341371477936:dw|

28. Calcmathlete

You're getting really good! $$\large\frac{(x + 1)(x + 1)}{(x + 3)(x - 1)} \times \frac{(x - 1)(x - 1)}{(x + 3)(x + 1)} = \frac{\cancel{(x + 1)}(x + 1)}{(x + 3)\cancel{(x - 1)}} \times \frac{\cancel{(x - 1)}(x - 1)}{(x + 3)\cancel{(x + 1)}} = \frac{(x + 1)(x - 1)}{(x + 3)(x + 3)}$$Yup :) You got it!

29. burhan101

Thankyou so much ! :)

30. burhan101

so this is the farthest it ca be simplified right