## anonymous 3 years ago simplify

1. anonymous

$(x+1)^{2}/x^2+2x-3 \times x^2-2x+1/x^2+4x+3$

2. anonymous

|dw:1341370090447:dw|

3. anonymous

$$\huge\text{Is the problem: }\frac{(x + 1)^{2}}{x^{2} + 2x - 3} \times \frac{x^{2} - 2x + 1}{x^{2} + 2x + 3}?$$

4. anonymous

yes, i didnt know how to type it in the equation like that

5. anonymous

You have to use the equation editor with a few extra steps. I assume you know how to factor the three trinomials?

6. anonymous

Do you????

7. anonymous

im not sure

8. anonymous

here's what ive done so far

9. anonymous

can you please tell me if it's somewhat right

10. anonymous

Sure.

11. anonymous

|dw:1341370527396:dw|

12. anonymous

oh that's wrong, i factor right ?

13. anonymous

Um...before you do that, factor the three individual trinomials. Try factoring: $$x^{2} + 2x - 3$$.

14. anonymous

$(x-2)(x+1)$

15. anonymous

is that right?

16. anonymous

Not quite. What are factors of -3 that add to 2?

17. anonymous

-2,-1

18. anonymous

No. -2 x -1 = 2. Not -3. You did it the opposite way. They should add to 2 and multiply to -3.

19. anonymous

OHH ! okay

20. anonymous

-1,3

21. anonymous

YAY! $$x^{2} + 2x - 3 = (x - 1)(x + 3)$$ Now, let's factor $$x^{2} - 2x + 1$$

22. anonymous

-1,-1

23. anonymous

(x-1)(x-1)

24. anonymous

Yup. Now finally, let's factor x^{2} + 4x + 3

25. anonymous

(x+3)(x+1)

26. anonymous

|dw:1341371332480:dw|

27. anonymous

|dw:1341371477936:dw|

28. anonymous

You're getting really good! $$\large\frac{(x + 1)(x + 1)}{(x + 3)(x - 1)} \times \frac{(x - 1)(x - 1)}{(x + 3)(x + 1)} = \frac{\cancel{(x + 1)}(x + 1)}{(x + 3)\cancel{(x - 1)}} \times \frac{\cancel{(x - 1)}(x - 1)}{(x + 3)\cancel{(x + 1)}} = \frac{(x + 1)(x - 1)}{(x + 3)(x + 3)}$$Yup :) You got it!

29. anonymous

Thankyou so much ! :)

30. anonymous

so this is the farthest it ca be simplified right