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minimum possible value of K for which the equation 2x^2+6x+K=0 has complex roots?
 one year ago
 one year ago
minimum possible value of K for which the equation 2x^2+6x+K=0 has complex roots?
 one year ago
 one year ago

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mukushlaBest ResponseYou've already chosen the best response.0
for having complex roots Discriminant of quadratic equation must be less than zero then what is result?
 one year ago

jkasdhkBest ResponseYou've already chosen the best response.0
its 9/2 (4.5)<0. Will the answer be 4?
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
\[2x^2+6x+K=0\] has complex roots when the discriminate is <0 \[\Delta=b^24ac\]\[=6^24\times1\times K\]
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
because in the quadratic formula we have to take the square root of the discriminant , \[x=\frac{b\pm\sqrt\Delta}{2a}\]
 one year ago

CallistoBest ResponseYou've already chosen the best response.0
Little correction for the above post... Δ=b^2  4ac = (6)^2  4(2)(K) < 0 Now you need to solve this: (6)^2  4(2)(K) < 0
 one year ago
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