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soccergal12

  • 3 years ago

find the absolute extrema of the following function on the given interval: f(x) = x^2 / (x^2 + 3) , [-1,1]

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  1. mathteacher1729
    • 3 years ago
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    I guess you have to use calculus and are not allowed to use a calculator?

  2. soccergal12
    • 3 years ago
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    yeah, we aren't allowed to use a calculator

  3. eliassaab
    • 3 years ago
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    \[ f'(x)=\frac{6 x}{\left(x^2+3\right)^2}\\ f'(x) >0 \text { if} x >0\\ f'(x) <0 \text { if} x<0\\ f'(x) =0 \text { if} x=0\\ \]

  4. mathteacher1729
    • 3 years ago
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    Do you know how to use the 1st derivative test?

  5. eliassaab
    • 3 years ago
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    Hence we have to examine f(1)=1/4 f(-1)=1/4 f(0)=0 Max 1/4 and Min=0

  6. soccergal12
    • 3 years ago
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    oh okay. thank you

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