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soccergal12
 3 years ago
find the absolute extrema of the following function on the given interval:
f(x) = x^2 / (x^2 + 3) , [1,1]
soccergal12
 3 years ago
find the absolute extrema of the following function on the given interval: f(x) = x^2 / (x^2 + 3) , [1,1]

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mathteacher1729
 3 years ago
Best ResponseYou've already chosen the best response.0I guess you have to use calculus and are not allowed to use a calculator?

soccergal12
 3 years ago
Best ResponseYou've already chosen the best response.0yeah, we aren't allowed to use a calculator

eliassaab
 3 years ago
Best ResponseYou've already chosen the best response.2\[ f'(x)=\frac{6 x}{\left(x^2+3\right)^2}\\ f'(x) >0 \text { if} x >0\\ f'(x) <0 \text { if} x<0\\ f'(x) =0 \text { if} x=0\\ \]

mathteacher1729
 3 years ago
Best ResponseYou've already chosen the best response.0Do you know how to use the 1st derivative test?

eliassaab
 3 years ago
Best ResponseYou've already chosen the best response.2Hence we have to examine f(1)=1/4 f(1)=1/4 f(0)=0 Max 1/4 and Min=0
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