Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
find the absolute extrema of the following function on the given interval:
f(x) = x^2 / (x^2 + 3) , [1,1]
 one year ago
 one year ago
find the absolute extrema of the following function on the given interval: f(x) = x^2 / (x^2 + 3) , [1,1]
 one year ago
 one year ago

This Question is Closed

mathteacher1729Best ResponseYou've already chosen the best response.0
I guess you have to use calculus and are not allowed to use a calculator?
 one year ago

soccergal12Best ResponseYou've already chosen the best response.0
yeah, we aren't allowed to use a calculator
 one year ago

eliassaabBest ResponseYou've already chosen the best response.2
\[ f'(x)=\frac{6 x}{\left(x^2+3\right)^2}\\ f'(x) >0 \text { if} x >0\\ f'(x) <0 \text { if} x<0\\ f'(x) =0 \text { if} x=0\\ \]
 one year ago

mathteacher1729Best ResponseYou've already chosen the best response.0
Do you know how to use the 1st derivative test?
 one year ago

eliassaabBest ResponseYou've already chosen the best response.2
Hence we have to examine f(1)=1/4 f(1)=1/4 f(0)=0 Max 1/4 and Min=0
 one year ago

soccergal12Best ResponseYou've already chosen the best response.0
oh okay. thank you
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.