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find the absolute extrema of the following function on the given interval:
f(x) = 6  (3x / (x^2 + 1)) , [0, positive infinity]
 one year ago
 one year ago
find the absolute extrema of the following function on the given interval: f(x) = 6  (3x / (x^2 + 1)) , [0, positive infinity]
 one year ago
 one year ago

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dpaIncBest ResponseYou've already chosen the best response.1
do you have the df/dx ?
 one year ago

soccergal12Best ResponseYou've already chosen the best response.0
i found that the absolute max was 7.5 and the absolute min is 4.5
 one year ago

dpaIncBest ResponseYou've already chosen the best response.1
remember to use the interval given...
 one year ago

mukushlaBest ResponseYou've already chosen the best response.2
@soccergal12 your answers are right
 one year ago

dpaIncBest ResponseYou've already chosen the best response.1
on the interval given, your answer is incorrect....
 one year ago

dpaIncBest ResponseYou've already chosen the best response.1
the interval he/she is looking at is [0, infintiy)
 one year ago

mukushlaBest ResponseYou've already chosen the best response.2
oh yes x=1 is not in the interval u r right then absolute maxima is f(0)=6 and absolute minima is f(1)=4.5 am i right?
 one year ago

soccergal12Best ResponseYou've already chosen the best response.0
oh, yeah. thank you! i didn't realize that either
 one year ago
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