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soccergal12 Group Title

find the absolute extrema of the following function on the given interval: f(x) = 6 - (3x / (x^2 + 1)) , [0, positive infinity]

  • 2 years ago
  • 2 years ago

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  1. dpaInc Group Title
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    do you have the df/dx ?

    • 2 years ago
  2. soccergal12 Group Title
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    i found that the absolute max was 7.5 and the absolute min is 4.5

    • 2 years ago
  3. dpaInc Group Title
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    remember to use the interval given...

    • 2 years ago
  4. mukushla Group Title
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    @soccergal12 your answers are right

    • 2 years ago
  5. soccergal12 Group Title
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    okay thank you

    • 2 years ago
  6. dpaInc Group Title
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    on the interval given, your answer is incorrect....

    • 2 years ago
  7. mukushla Group Title
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    oh...Oh why?!

    • 2 years ago
  8. mukushla Group Title
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    @dpaInc

    • 2 years ago
  9. dpaInc Group Title
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    the interval he/she is looking at is [0, infintiy)

    • 2 years ago
  10. mukushla Group Title
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    well

    • 2 years ago
  11. dpaInc Group Title
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    max is at x=0, f(0)=6

    • 2 years ago
  12. mukushla Group Title
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    oh yes x=-1 is not in the interval u r right then absolute maxima is f(0)=6 and absolute minima is f(1)=4.5 am i right?

    • 2 years ago
  13. dpaInc Group Title
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    yep...:)

    • 2 years ago
  14. mukushla Group Title
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    @dplanc thank u

    • 2 years ago
  15. mukushla Group Title
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    @soccergal12

    • 2 years ago
  16. soccergal12 Group Title
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    oh, yeah. thank you! i didn't realize that either

    • 2 years ago
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