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soccergal12
Group Title
find the absolute extrema of the following function on the given interval:
f(x) = 6  (3x / (x^2 + 1)) , [0, positive infinity]
 2 years ago
 2 years ago
soccergal12 Group Title
find the absolute extrema of the following function on the given interval: f(x) = 6  (3x / (x^2 + 1)) , [0, positive infinity]
 2 years ago
 2 years ago

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dpaInc Group TitleBest ResponseYou've already chosen the best response.1
do you have the df/dx ?
 2 years ago

soccergal12 Group TitleBest ResponseYou've already chosen the best response.0
i found that the absolute max was 7.5 and the absolute min is 4.5
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.1
remember to use the interval given...
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.2
@soccergal12 your answers are right
 2 years ago

soccergal12 Group TitleBest ResponseYou've already chosen the best response.0
okay thank you
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.1
on the interval given, your answer is incorrect....
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.2
oh...Oh why?!
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.1
the interval he/she is looking at is [0, infintiy)
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.1
max is at x=0, f(0)=6
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.2
oh yes x=1 is not in the interval u r right then absolute maxima is f(0)=6 and absolute minima is f(1)=4.5 am i right?
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.2
@dplanc thank u
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.2
@soccergal12
 2 years ago

soccergal12 Group TitleBest ResponseYou've already chosen the best response.0
oh, yeah. thank you! i didn't realize that either
 2 years ago
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