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find the absolute extrema of the following function on the given interval: f(x) = 6 - (3x / (x^2 + 1)) , [0, positive infinity]

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do you have the df/dx ?
i found that the absolute max was 7.5 and the absolute min is 4.5
remember to use the interval given...

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Other answers:

@soccergal12 your answers are right
okay thank you
on the interval given, your answer is incorrect....
oh...Oh why?!
the interval he/she is looking at is [0, infintiy)
max is at x=0, f(0)=6
oh yes x=-1 is not in the interval u r right then absolute maxima is f(0)=6 and absolute minima is f(1)=4.5 am i right?
@dplanc thank u
oh, yeah. thank you! i didn't realize that either

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