soccergal12
find the absolute extrema of the following function on the given interval:
f(x) = 6  (3x / (x^2 + 1)) , [0, positive infinity]



This Question is Closed

dpaInc
Best Response
You've already chosen the best response.
1
do you have the df/dx ?

soccergal12
Best Response
You've already chosen the best response.
0
i found that the absolute max was 7.5 and the absolute min is 4.5

dpaInc
Best Response
You've already chosen the best response.
1
remember to use the interval given...

mukushla
Best Response
You've already chosen the best response.
2
@soccergal12
your answers are right

soccergal12
Best Response
You've already chosen the best response.
0
okay thank you

dpaInc
Best Response
You've already chosen the best response.
1
on the interval given, your answer is incorrect....

mukushla
Best Response
You've already chosen the best response.
2
oh...Oh why?!

mukushla
Best Response
You've already chosen the best response.
2
@dpaInc

dpaInc
Best Response
You've already chosen the best response.
1
the interval he/she is looking at is [0, infintiy)

mukushla
Best Response
You've already chosen the best response.
2
well

dpaInc
Best Response
You've already chosen the best response.
1
max is at x=0, f(0)=6

mukushla
Best Response
You've already chosen the best response.
2
oh yes x=1 is not in the interval u r right
then absolute maxima is f(0)=6
and absolute minima is f(1)=4.5
am i right?

dpaInc
Best Response
You've already chosen the best response.
1
yep...:)

mukushla
Best Response
You've already chosen the best response.
2
@dplanc thank u

mukushla
Best Response
You've already chosen the best response.
2
@soccergal12

soccergal12
Best Response
You've already chosen the best response.
0
oh, yeah. thank you! i didn't realize that either