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soccergal12

  • 3 years ago

find the absolute extrema of the following function on the given interval: f(x) = 6 - (3x / (x^2 + 1)) , [0, positive infinity]

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  1. dpaInc
    • 3 years ago
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    do you have the df/dx ?

  2. soccergal12
    • 3 years ago
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    i found that the absolute max was 7.5 and the absolute min is 4.5

  3. dpaInc
    • 3 years ago
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    remember to use the interval given...

  4. mukushla
    • 3 years ago
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    @soccergal12 your answers are right

  5. soccergal12
    • 3 years ago
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    okay thank you

  6. dpaInc
    • 3 years ago
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    on the interval given, your answer is incorrect....

  7. mukushla
    • 3 years ago
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    oh...Oh why?!

  8. mukushla
    • 3 years ago
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    @dpaInc

  9. dpaInc
    • 3 years ago
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    the interval he/she is looking at is [0, infintiy)

  10. mukushla
    • 3 years ago
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    well

  11. dpaInc
    • 3 years ago
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    max is at x=0, f(0)=6

  12. mukushla
    • 3 years ago
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    oh yes x=-1 is not in the interval u r right then absolute maxima is f(0)=6 and absolute minima is f(1)=4.5 am i right?

  13. dpaInc
    • 3 years ago
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    yep...:)

  14. mukushla
    • 3 years ago
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    @dplanc thank u

  15. mukushla
    • 3 years ago
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    @soccergal12

  16. soccergal12
    • 3 years ago
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    oh, yeah. thank you! i didn't realize that either

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