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soccergal12
 2 years ago
find the absolute extrema of the following function on the given interval:
f(x) = 6  (3x / (x^2 + 1)) , [0, positive infinity]
soccergal12
 2 years ago
find the absolute extrema of the following function on the given interval: f(x) = 6  (3x / (x^2 + 1)) , [0, positive infinity]

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soccergal12
 2 years ago
Best ResponseYou've already chosen the best response.0i found that the absolute max was 7.5 and the absolute min is 4.5

dpaInc
 2 years ago
Best ResponseYou've already chosen the best response.1remember to use the interval given...

mukushla
 2 years ago
Best ResponseYou've already chosen the best response.2@soccergal12 your answers are right

dpaInc
 2 years ago
Best ResponseYou've already chosen the best response.1on the interval given, your answer is incorrect....

dpaInc
 2 years ago
Best ResponseYou've already chosen the best response.1the interval he/she is looking at is [0, infintiy)

mukushla
 2 years ago
Best ResponseYou've already chosen the best response.2oh yes x=1 is not in the interval u r right then absolute maxima is f(0)=6 and absolute minima is f(1)=4.5 am i right?

soccergal12
 2 years ago
Best ResponseYou've already chosen the best response.0oh, yeah. thank you! i didn't realize that either
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