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anonymous
 4 years ago
find all relative extrema and points of inflection:
f(x) = 2 / (x^2  4)
i got x^2 = 4/3 as an inflection point. but i think i did something wrong
anonymous
 4 years ago
find all relative extrema and points of inflection: f(x) = 2 / (x^2  4) i got x^2 = 4/3 as an inflection point. but i think i did something wrong

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no... nothing wrong there... what happens when you take the square root of a negative number?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well you can't take a sqaure root of a negative number. so i wouldn't have any inflection points right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0right... that's what that means...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but that does not mean the graph is all concave up or all concave down.... there can be places on your graph where in one interval its ccup and in another it's ccdown...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay, the question does not ask for concavity, but should i still determine if there is some type of concavity? just to be safe?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry... hate when chrome crashes... no we don't need concavity but the question did ask for points of inflection...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so according to what u got, there are no points of inflection...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0now all you need are relative max/mins... do you have your first derivative?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes , it was (4x) / (x^2 4)^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so what's your critical number(s) ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.00, 2 and 2, i said there was a relatve max at (0, 1/2)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok.... now do the first derivative test on the intervals: (infinity, 2) (2, 0) (0, 2) (2, infinity)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i did that and found the relative max

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh... sorry... i guess you're done...:)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0perfect. thank you :)
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