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find all relative extrema and points of inflection:
f(x) = 2 / (x^2  4)
i got x^2 = 4/3 as an inflection point. but i think i did something wrong
 one year ago
 one year ago
find all relative extrema and points of inflection: f(x) = 2 / (x^2  4) i got x^2 = 4/3 as an inflection point. but i think i did something wrong
 one year ago
 one year ago

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dpaIncBest ResponseYou've already chosen the best response.1
no... nothing wrong there... what happens when you take the square root of a negative number?
 one year ago

soccergal12Best ResponseYou've already chosen the best response.0
well you can't take a sqaure root of a negative number. so i wouldn't have any inflection points right?
 one year ago

dpaIncBest ResponseYou've already chosen the best response.1
right... that's what that means...
 one year ago

dpaIncBest ResponseYou've already chosen the best response.1
but that does not mean the graph is all concave up or all concave down.... there can be places on your graph where in one interval its ccup and in another it's ccdown...
 one year ago

soccergal12Best ResponseYou've already chosen the best response.0
okay, the question does not ask for concavity, but should i still determine if there is some type of concavity? just to be safe?
 one year ago

dpaIncBest ResponseYou've already chosen the best response.1
sorry... hate when chrome crashes... no we don't need concavity but the question did ask for points of inflection...
 one year ago

dpaIncBest ResponseYou've already chosen the best response.1
so according to what u got, there are no points of inflection...
 one year ago

dpaIncBest ResponseYou've already chosen the best response.1
now all you need are relative max/mins... do you have your first derivative?
 one year ago

soccergal12Best ResponseYou've already chosen the best response.0
yes , it was (4x) / (x^2 4)^2
 one year ago

dpaIncBest ResponseYou've already chosen the best response.1
so what's your critical number(s) ?
 one year ago

soccergal12Best ResponseYou've already chosen the best response.0
0, 2 and 2, i said there was a relatve max at (0, 1/2)
 one year ago

dpaIncBest ResponseYou've already chosen the best response.1
ok.... now do the first derivative test on the intervals: (infinity, 2) (2, 0) (0, 2) (2, infinity)
 one year ago

soccergal12Best ResponseYou've already chosen the best response.0
i did that and found the relative max
 one year ago

dpaIncBest ResponseYou've already chosen the best response.1
oh... sorry... i guess you're done...:)
 one year ago

soccergal12Best ResponseYou've already chosen the best response.0
perfect. thank you :)
 one year ago
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