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hi what is the factor of 2x^2-3x-9?

Mathematics
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2x^2 - 3x - 9 break down the middle term 2x^2 + 6x - 3x - 9 group them (2x^2 + 6x) - (3x + 9) factor out 2x(x + 3) - 3(x+3) do you see it now?
\[x^2-3x-9=0\] \[x^2-6x+3x-9=0\] \[2x(x-3)+3(x-3)=0\] now you try to simplify.
you can use the quadratic formula i.e \[-b \pm \sqrt{b ^{2}-4ac}/2a\] here a=2 b=-3 c=-9 put the values of a, b and c in equation and you'll get your answer

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Other answers:

thanks for helping me
factor of 2x+8
28X+7
we have to make the first term of these sums.
I CANNOT SOLVE THAT ONE
wait i am doing.
hi what is the factor of 8x^3-216
2x+342
\[First Term= (Middle Term)^2/4*(Last Term)\]
thanks,but im not asking what is the procedure im asking is what is the solution?
kantutan
gago ka talaga
oo nga pala tuloy ung sa e nglish
tar a abano Joke :D
factor of 8x^3-216 \[8x(x^2-27)=0\] \[8x=0 \] \[x=0\] or \[x^2-27=0\] \[x^2=27\] \[x=\sqrt{27}\]
abano add mo ko sa fwend m!!
(x-6)(x+3)
@danny_dumond Please don't post only answers as that's against the Code of Conduct: http://openstudy.com/code-of-conduct
well find something like (cx+a) (dx+b) to = 2x^2-3x-9
Gosh sorry! :P

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