joemarie
hi what is the factor of 2x^2-3x-9?
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lgbasallote
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2x^2 - 3x - 9
break down the middle term
2x^2 + 6x - 3x - 9
group them
(2x^2 + 6x) - (3x + 9)
factor out
2x(x + 3) - 3(x+3)
do you see it now?
muhammad9t5
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\[x^2-3x-9=0\]
\[x^2-6x+3x-9=0\]
\[2x(x-3)+3(x-3)=0\]
now you try to simplify.
annas
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you can use the quadratic formula i.e
\[-b \pm \sqrt{b ^{2}-4ac}/2a\]
here a=2
b=-3
c=-9
put the values of a, b and c in equation and you'll get your answer
joemarie
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thanks for helping me
joemarie
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factor of 2x+8
abano
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28X+7
muhammad9t5
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we have to make the first term of these sums.
abano
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I CANNOT SOLVE THAT ONE
muhammad9t5
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wait i am doing.
joemarie
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hi what is the factor of 8x^3-216
abano
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2x+342
muhammad9t5
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\[First Term= (Middle Term)^2/4*(Last Term)\]
joemarie
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thanks,but im not asking what is the procedure im asking is what is the solution?
abano
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kantutan
joemarie
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gago ka talaga
joemarie
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oo nga pala tuloy ung sa e
nglish
joemarie
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tar
a abano
Joke :D
muhammad9t5
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factor of 8x^3-216
\[8x(x^2-27)=0\]
\[8x=0 \]
\[x=0\]
or \[x^2-27=0\]
\[x^2=27\]
\[x=\sqrt{27}\]
joemarie
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abano add mo ko sa fwend m!!
danny_dumond
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(x-6)(x+3)
timo86m
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well find
something like
(cx+a) (dx+b) to = 2x^2-3x-9
danny_dumond
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Gosh sorry! :P