## joemarie 3 years ago hi what is the factor of 2x^2-3x-9?

1. lgbasallote

2x^2 - 3x - 9 break down the middle term 2x^2 + 6x - 3x - 9 group them (2x^2 + 6x) - (3x + 9) factor out 2x(x + 3) - 3(x+3) do you see it now?

$x^2-3x-9=0$ $x^2-6x+3x-9=0$ $2x(x-3)+3(x-3)=0$ now you try to simplify.

3. annas

you can use the quadratic formula i.e $-b \pm \sqrt{b ^{2}-4ac}/2a$ here a=2 b=-3 c=-9 put the values of a, b and c in equation and you'll get your answer

4. joemarie

thanks for helping me

5. joemarie

factor of 2x+8

6. abano

28X+7

we have to make the first term of these sums.

8. abano

I CANNOT SOLVE THAT ONE

wait i am doing.

10. joemarie

hi what is the factor of 8x^3-216

11. abano

2x+342

$First Term= (Middle Term)^2/4*(Last Term)$

13. joemarie

thanks,but im not asking what is the procedure im asking is what is the solution?

14. abano

kantutan

15. joemarie

gago ka talaga

16. joemarie

oo nga pala tuloy ung sa e nglish

17. joemarie

tar a abano Joke :D

factor of 8x^3-216 $8x(x^2-27)=0$ $8x=0$ $x=0$ or $x^2-27=0$ $x^2=27$ $x=\sqrt{27}$

19. joemarie

abano add mo ko sa fwend m!!

20. danny_dumond

(x-6)(x+3)

21. Wired

@danny_dumond Please don't post only answers as that's against the Code of Conduct: http://openstudy.com/code-of-conduct

22. timo86m

well find something like (cx+a) (dx+b) to = 2x^2-3x-9

23. danny_dumond

Gosh sorry! :P