## anonymous 4 years ago hi what is the factor of 2x^2-3x-9?

1. lgbasallote

2x^2 - 3x - 9 break down the middle term 2x^2 + 6x - 3x - 9 group them (2x^2 + 6x) - (3x + 9) factor out 2x(x + 3) - 3(x+3) do you see it now?

2. anonymous

$x^2-3x-9=0$ $x^2-6x+3x-9=0$ $2x(x-3)+3(x-3)=0$ now you try to simplify.

3. anonymous

you can use the quadratic formula i.e $-b \pm \sqrt{b ^{2}-4ac}/2a$ here a=2 b=-3 c=-9 put the values of a, b and c in equation and you'll get your answer

4. anonymous

thanks for helping me

5. anonymous

factor of 2x+8

6. anonymous

28X+7

7. anonymous

we have to make the first term of these sums.

8. anonymous

I CANNOT SOLVE THAT ONE

9. anonymous

wait i am doing.

10. anonymous

hi what is the factor of 8x^3-216

11. anonymous

2x+342

12. anonymous

$First Term= (Middle Term)^2/4*(Last Term)$

13. anonymous

thanks,but im not asking what is the procedure im asking is what is the solution?

14. anonymous

kantutan

15. anonymous

gago ka talaga

16. anonymous

oo nga pala tuloy ung sa e nglish

17. anonymous

tar a abano Joke :D

18. anonymous

factor of 8x^3-216 $8x(x^2-27)=0$ $8x=0$ $x=0$ or $x^2-27=0$ $x^2=27$ $x=\sqrt{27}$

19. anonymous

abano add mo ko sa fwend m!!

20. anonymous

(x-6)(x+3)

21. anonymous

@danny_dumond Please don't post only answers as that's against the Code of Conduct: http://openstudy.com/code-of-conduct

22. anonymous

well find something like (cx+a) (dx+b) to = 2x^2-3x-9

23. anonymous

Gosh sorry! :P