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joemarie

hi what is the factor of 2x^2-3x-9?

  • one year ago
  • one year ago

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  1. lgbasallote
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    2x^2 - 3x - 9 break down the middle term 2x^2 + 6x - 3x - 9 group them (2x^2 + 6x) - (3x + 9) factor out 2x(x + 3) - 3(x+3) do you see it now?

    • one year ago
  2. muhammad9t5
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    \[x^2-3x-9=0\] \[x^2-6x+3x-9=0\] \[2x(x-3)+3(x-3)=0\] now you try to simplify.

    • one year ago
  3. annas
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    you can use the quadratic formula i.e \[-b \pm \sqrt{b ^{2}-4ac}/2a\] here a=2 b=-3 c=-9 put the values of a, b and c in equation and you'll get your answer

    • one year ago
  4. joemarie
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    thanks for helping me

    • one year ago
  5. joemarie
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    factor of 2x+8

    • one year ago
  6. abano
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    28X+7

    • one year ago
  7. muhammad9t5
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    we have to make the first term of these sums.

    • one year ago
  8. abano
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    I CANNOT SOLVE THAT ONE

    • one year ago
  9. muhammad9t5
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    wait i am doing.

    • one year ago
  10. joemarie
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    hi what is the factor of 8x^3-216

    • one year ago
  11. abano
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    2x+342

    • one year ago
  12. muhammad9t5
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    \[First Term= (Middle Term)^2/4*(Last Term)\]

    • one year ago
  13. joemarie
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    thanks,but im not asking what is the procedure im asking is what is the solution?

    • one year ago
  14. abano
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    kantutan

    • one year ago
  15. joemarie
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    gago ka talaga

    • one year ago
  16. joemarie
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    oo nga pala tuloy ung sa e nglish

    • one year ago
  17. joemarie
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    tar a abano Joke :D

    • one year ago
  18. muhammad9t5
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    factor of 8x^3-216 \[8x(x^2-27)=0\] \[8x=0 \] \[x=0\] or \[x^2-27=0\] \[x^2=27\] \[x=\sqrt{27}\]

    • one year ago
  19. joemarie
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    abano add mo ko sa fwend m!!

    • one year ago
  20. danny_dumond
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    (x-6)(x+3)

    • one year ago
  21. Wired
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    @danny_dumond Please don't post only answers as that's against the Code of Conduct: http://openstudy.com/code-of-conduct

    • one year ago
  22. timo86m
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    well find something like (cx+a) (dx+b) to = 2x^2-3x-9

    • one year ago
  23. danny_dumond
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    Gosh sorry! :P

    • one year ago
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