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lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.12x^2  3x  9 break down the middle term 2x^2 + 6x  3x  9 group them (2x^2 + 6x)  (3x + 9) factor out 2x(x + 3)  3(x+3) do you see it now?

muhammad9t5
 2 years ago
Best ResponseYou've already chosen the best response.1\[x^23x9=0\] \[x^26x+3x9=0\] \[2x(x3)+3(x3)=0\] now you try to simplify.

annas
 2 years ago
Best ResponseYou've already chosen the best response.0you can use the quadratic formula i.e \[b \pm \sqrt{b ^{2}4ac}/2a\] here a=2 b=3 c=9 put the values of a, b and c in equation and you'll get your answer

muhammad9t5
 2 years ago
Best ResponseYou've already chosen the best response.1we have to make the first term of these sums.

joemarie
 2 years ago
Best ResponseYou've already chosen the best response.2hi what is the factor of 8x^3216

muhammad9t5
 2 years ago
Best ResponseYou've already chosen the best response.1\[First Term= (Middle Term)^2/4*(Last Term)\]

joemarie
 2 years ago
Best ResponseYou've already chosen the best response.2thanks,but im not asking what is the procedure im asking is what is the solution?

joemarie
 2 years ago
Best ResponseYou've already chosen the best response.2oo nga pala tuloy ung sa e nglish

muhammad9t5
 2 years ago
Best ResponseYou've already chosen the best response.1factor of 8x^3216 \[8x(x^227)=0\] \[8x=0 \] \[x=0\] or \[x^227=0\] \[x^2=27\] \[x=\sqrt{27}\]

joemarie
 2 years ago
Best ResponseYou've already chosen the best response.2abano add mo ko sa fwend m!!

Wired
 2 years ago
Best ResponseYou've already chosen the best response.0@danny_dumond Please don't post only answers as that's against the Code of Conduct: http://openstudy.com/codeofconduct

timo86m
 2 years ago
Best ResponseYou've already chosen the best response.0well find something like (cx+a) (dx+b) to = 2x^23x9
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