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 2 years ago
How do you change the bounds/limits on the integrand for a parametric equation? I understand the integralbased area formula for Cartesian equations fine, but I'm a bit lost here and could definitely use some clarification help. :)
 2 years ago
How do you change the bounds/limits on the integrand for a parametric equation? I understand the integralbased area formula for Cartesian equations fine, but I'm a bit lost here and could definitely use some clarification help. :)

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agentx5
 2 years ago
Best ResponseYou've already chosen the best response.0Cartesian mode: \[Area = \huge \int\limits_{a}^{b} f(x) dx\] Parametric mode? \[Area =\huge \int\limits_{\alpha}^{\beta} g(t) \cdot f'(t) \ dt\] The heck is this?

agentx5
 2 years ago
Best ResponseYou've already chosen the best response.0\[\huge slope = \frac{(\frac{dy}{dt})}{(\frac{dx}{dt})}\]

agentx5
 2 years ago
Best ResponseYou've already chosen the best response.0What I'm not understanding is where my substitution is coming from. Maybe a simple example is in order, let me go find one...

agentx5
 2 years ago
Best ResponseYou've already chosen the best response.0Example from the homework, verbatim: Find an equation of the tangent to the curve at the given point by both eliminating the parameter and without eliminating the parameter. x = 6 + lnt, y = t^2 + 6, (6, 7)

malevolence19
 2 years ago
Best ResponseYou've already chosen the best response.0By (6,7) do you mean from 6 to 7?

agentx5
 2 years ago
Best ResponseYou've already chosen the best response.0Ah nope @malevolence19, it's the point there

agentx5
 2 years ago
Best ResponseYou've already chosen the best response.0I presume it means the graph contains that point, or the tangent line & the graph both do more specifically.

agentx5
 2 years ago
Best ResponseYou've already chosen the best response.0And one of the easier looking questions... Hmpf! I dislike lesson plans that give you supereasy examples in the lecture notes but then kick your brain around like a can when you get to the homework :P

agentx5
 2 years ago
Best ResponseYou've already chosen the best response.0It's like, oh hey you got any questions on this? No? Oh ok let's try something twenty times harder, ok jump! :D

malevolence19
 2 years ago
Best ResponseYou've already chosen the best response.0Do you know how to do with "eliminating the parameter"?
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