anonymous
  • anonymous
The foci of the following graph are (3+2 square root 2, -5) and (3-2square root 2,-5) ..TRUE OR FALSE
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
no graph?
anonymous
  • anonymous
any ideas?
NotTim
  • NotTim
hey, could you format the equation a bit better? I dunno, with the equation editor or drawing it out? Thx

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More answers

NotTim
  • NotTim
ask for help, dont reply.
NotTim
  • NotTim
thannk you
anonymous
  • anonymous
it looks like this
NotTim
  • NotTim
Just wondering, are you allowed to rearrange |dw:1341468139444:dw|
NotTim
  • NotTim
also, wahts a foci?
anonymous
  • anonymous
im not sure..If it helps get the question answered correctly
anonymous
  • anonymous
a sort of hyperboli
NotTim
  • NotTim
whats hyperboli?
anonymous
  • anonymous
hyperbola
NotTim
  • NotTim
whats hyperbola? (wow..i am stupid...)
anonymous
  • anonymous
a curve that lies on the plane!
NotTim
  • NotTim
Does the curve of these graphs lie on (3+2 square root 2, -5) and (3-2square root 2,-5) ?
anonymous
  • anonymous
i believe so?
NotTim
  • NotTim
What's your proof?
anonymous
  • anonymous
is it true. or false.. do you know?
NotTim
  • NotTim
Well. First figure out the functions of the graph, and then figure out if the foci of these 2 graphs.
NotTim
  • NotTim
I can't answer your quiz question cause I'm doing my own too! QUIZES FOR EVERYONE
anonymous
  • anonymous
its really simple..you cant just tell me if its true or false so i can move on??
farmdawgnation
  • farmdawgnation
Actually, no he can't.
farmdawgnation
  • farmdawgnation
http://openstudy.com/code-of-conduct "Don't provide someone with just the answer - explain the process, and help guide them through understanding the problem."
anonymous
  • anonymous
he can actually..its possible..you just would not like him too.
NotTim
  • NotTim
Actually, I'm a bot created by OpenStudy. I can only follow the rules outlined to be by the programming.
farmdawgnation
  • farmdawgnation
coolaidd, Your smart alec responses are beginning to wear thin on my patience. Tone down the attitude please. NotTim has been attempting to help guide you to the solution on your own. If you're just looking to find the answer then perhaps this isn't the best site for you?
anonymous
  • anonymous
-__-

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