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lolroark

Find the period of the minute hand of a wall clock. Find the angular frequency of the minute hand of a wall clock. Find the frequency of the minute hand of a wall clock.

  • one year ago
  • one year ago

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  1. lolroark
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    i can tell you that the period is 3600s, if you can also explain this i would be greatful

    • one year ago
  2. Ganpat
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    1. Period = 60 min * 60 = 3600 Sec 2. Angular velocity = (2 * Pi * N ) 60.. = ( 2 * pi * 360) / 60 = 37.699 . 3. Frequency = 1/N = 1/ 360 ... I guess, i am right... @Vaidehi09 : what say ? u good at Physics..

    • one year ago
  3. lolroark
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    it says that they are incorrect. thanks for trying.

    • one year ago
  4. Ganpat
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    lol, m sorry !!!

    • one year ago
  5. Vaidehi09
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    Period T is right. but angular velocity w = 2 pi /T = 2pi/3600 = 91/1800 rad/sec and frequency = 1/T = 1/3600

    • one year ago
  6. lolroark
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    it says angular velocity is 1.75*10^-3. is your answer in rad/s?

    • one year ago
  7. Ganpat
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    yes ..

    • one year ago
  8. lolroark
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    the frequency was 1/3600 thank you for that.

    • one year ago
  9. lolroark
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    can anyone explain angular velocity please? and thanks for the effort ganpat

    • one year ago
  10. Vaidehi09
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    hey wait.....there was a typing error....w = pi/1800 rad/s

    • one year ago
  11. lolroark
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    aww bummer, too bad i only had one try left on that question. thanks though now that i understand it better

    • one year ago
  12. Vaidehi09
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    glad to help :) just remember the formulae and it'll be a piece of cake!

    • one year ago
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