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Nick2019
Group Title
Frank kicks a soccer ball off the ground and in the air with an initial velocity of 30 feet per second. Using the formula H(t) = −16t2 + vt + s, what is the maximum height the soccer ball reaches?
14.1 feet
13.7 feet
13.2 feet
15.2 feet
 2 years ago
 2 years ago
Nick2019 Group Title
Frank kicks a soccer ball off the ground and in the air with an initial velocity of 30 feet per second. Using the formula H(t) = −16t2 + vt + s, what is the maximum height the soccer ball reaches? 14.1 feet 13.7 feet 13.2 feet 15.2 feet
 2 years ago
 2 years ago

This Question is Closed

zepp Group TitleBest ResponseYou've already chosen the best response.3
We are looking for the highest point of a facing down parabola, therefore the vertex of the parabola.
 2 years ago

zepp Group TitleBest ResponseYou've already chosen the best response.3
dw:1341586592338:dw
 2 years ago

SmoothMath Group TitleBest ResponseYou've already chosen the best response.0
Do your thing, Zeppy.
 2 years ago

Nick2019 Group TitleBest ResponseYou've already chosen the best response.0
so this means??
 2 years ago

Nick2019 Group TitleBest ResponseYou've already chosen the best response.0
lol i should have read the chapter :/
 2 years ago

zepp Group TitleBest ResponseYou've already chosen the best response.3
dw:1341586632841:dw
 2 years ago

SmoothMath Group TitleBest ResponseYou've already chosen the best response.0
GAHAHAHA YEEEESSSS
 2 years ago

Nick2019 Group TitleBest ResponseYou've already chosen the best response.0
lol so whats the answer, nice drawing
 2 years ago

SmoothMath Group TitleBest ResponseYou've already chosen the best response.0
The eeeeye, it sees everything!
 2 years ago

Nick2019 Group TitleBest ResponseYou've already chosen the best response.0
lol i moved my webcam away from me haha
 2 years ago

zepp Group TitleBest ResponseYou've already chosen the best response.3
H(t) = −16t2 + vt + s Represents the equation of your parabola, we are looking for the vertex, the xvalue of the vertex could be found by using the formula \[\frac{b}{2a}\]
 2 years ago

Nick2019 Group TitleBest ResponseYou've already chosen the best response.0
so one of these 14.1 feet 13.7 feet 13.2 feet 15.2 feet
 2 years ago

zepp Group TitleBest ResponseYou've already chosen the best response.3
Now, 30 feet per second. v=30 H(t) = −16t2 + 30t + s
 2 years ago

zepp Group TitleBest ResponseYou've already chosen the best response.3
Use the formula I wrote above :)
 2 years ago

Nick2019 Group TitleBest ResponseYou've already chosen the best response.0
dont know how to solve that :/ i just need the answer no offence
 2 years ago

Nick2019 Group TitleBest ResponseYou've already chosen the best response.0
ok il guess thanks for the help (in a good way)
 2 years ago

zepp Group TitleBest ResponseYou've already chosen the best response.3
A quadratic equation is \(ax^2+bx+c\) Where the x of the vertex is at \(\large \frac{b}{2a}\) In our equation H(t) = −16t2 + 30t + s b is 30 and a is 16 \[\frac{30}{2(16)}=\frac{30}{32}=\frac{30}{32}\]
 2 years ago

zepp Group TitleBest ResponseYou've already chosen the best response.3
What you have to do next it to replace this xvalue back into the equation to find the height (yvalue) And sorry I'm at work so I was afk :(
 2 years ago

Sav_1012 Group TitleBest ResponseYou've already chosen the best response.0
what is it
 one year ago
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