## Nick2019 Group Title Frank kicks a soccer ball off the ground and in the air with an initial velocity of 30 feet per second. Using the formula H(t) = −16t2 + vt + s, what is the maximum height the soccer ball reaches? 14.1 feet 13.7 feet 13.2 feet 15.2 feet 2 years ago 2 years ago

1. zepp Group Title

We are looking for the highest point of a facing down parabola, therefore the vertex of the parabola.

2. zepp Group Title

|dw:1341586592338:dw|

3. SmoothMath Group Title

4. Nick2019 Group Title

so this means??

5. Nick2019 Group Title

lol i should have read the chapter :/

6. zepp Group Title

|dw:1341586632841:dw|

7. zepp Group Title

Oh

8. SmoothMath Group Title

GAHAHAHA YEEEESSSS

9. Nick2019 Group Title

lol so whats the answer, nice drawing

10. SmoothMath Group Title

The eeeeye, it sees everything!

11. Nick2019 Group Title

lol i moved my webcam away from me haha

12. zepp Group Title

H(t) = −16t2 + vt + s Represents the equation of your parabola, we are looking for the vertex, the x-value of the vertex could be found by using the formula $\frac{-b}{2a}$

13. Nick2019 Group Title

so one of these 14.1 feet 13.7 feet 13.2 feet 15.2 feet

14. zepp Group Title

Now, 30 feet per second. v=30 H(t) = −16t2 + 30t + s

15. zepp Group Title

Use the formula I wrote above :)

16. Nick2019 Group Title

dont know how to solve that :/ i just need the answer no offence

17. Nick2019 Group Title

ok il guess thanks for the help (in a good way)

18. zepp Group Title

A quadratic equation is $$ax^2+bx+c$$ Where the x of the vertex is at $$\large \frac{-b}{2a}$$ In our equation H(t) = −16t2 + 30t + s b is 30 and a is -16 $\frac{-30}{2(-16)}=\frac{-30}{-32}=\frac{30}{32}$

19. zepp Group Title

What you have to do next it to replace this x-value back into the equation to find the height (y-value) And sorry I'm at work so I was afk :(

20. Sav_1012 Group Title

what is it