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Frank kicks a soccer ball off the ground and in the air with an initial velocity of 30 feet per second. Using the formula H(t) = −16t2 + vt + s, what is the maximum height the soccer ball reaches? 14.1 feet 13.7 feet 13.2 feet 15.2 feet

Mathematics
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We are looking for the highest point of a facing down parabola, therefore the vertex of the parabola.
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Do your thing, Zeppy.

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Other answers:

so this means??
lol i should have read the chapter :/
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Oh
GAHAHAHA YEEEESSSS
lol so whats the answer, nice drawing
The eeeeye, it sees everything!
lol i moved my webcam away from me haha
H(t) = −16t2 + vt + s Represents the equation of your parabola, we are looking for the vertex, the x-value of the vertex could be found by using the formula \[\frac{-b}{2a}\]
so one of these 14.1 feet 13.7 feet 13.2 feet 15.2 feet
Now, 30 feet per second. v=30 H(t) = −16t2 + 30t + s
Use the formula I wrote above :)
dont know how to solve that :/ i just need the answer no offence
ok il guess thanks for the help (in a good way)
A quadratic equation is \(ax^2+bx+c\) Where the x of the vertex is at \(\large \frac{-b}{2a}\) In our equation H(t) = −16t2 + 30t + s b is 30 and a is -16 \[\frac{-30}{2(-16)}=\frac{-30}{-32}=\frac{30}{32}\]
What you have to do next it to replace this x-value back into the equation to find the height (y-value) And sorry I'm at work so I was afk :(
what is it

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