Nick2019
Frank kicks a soccer ball off the ground and in the air with an initial velocity of 30 feet per second. Using the formula H(t) = −16t2 + vt + s, what is the maximum height the soccer ball reaches?
14.1 feet
13.7 feet
13.2 feet
15.2 feet
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zepp
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We are looking for the highest point of a facing down parabola, therefore the vertex of the parabola.
zepp
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|dw:1341586592338:dw|
SmoothMath
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Do your thing, Zeppy.
Nick2019
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so this means??
Nick2019
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lol i should have read the chapter :/
zepp
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|dw:1341586632841:dw|
zepp
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Oh
SmoothMath
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GAHAHAHA YEEEESSSS
Nick2019
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lol so whats the answer, nice drawing
SmoothMath
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The eeeeye, it sees everything!
Nick2019
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lol i moved my webcam away from me haha
zepp
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H(t) = −16t2 + vt + s
Represents the equation of your parabola, we are looking for the vertex, the x-value of the vertex could be found by using the formula \[\frac{-b}{2a}\]
Nick2019
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so one of these
14.1 feet 13.7 feet 13.2 feet 15.2 feet
zepp
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Now, 30 feet per second.
v=30
H(t) = −16t2 + 30t + s
zepp
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Use the formula I wrote above :)
Nick2019
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dont know how to solve that :/ i just need the answer no offence
Nick2019
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ok il guess thanks for the help (in a good way)
zepp
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A quadratic equation is \(ax^2+bx+c\)
Where the x of the vertex is at \(\large \frac{-b}{2a}\)
In our equation H(t) = −16t2 + 30t + s
b is 30
and a is -16
\[\frac{-30}{2(-16)}=\frac{-30}{-32}=\frac{30}{32}\]
zepp
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What you have to do next it to replace this x-value back into the equation to find the height (y-value)
And sorry I'm at work so I was afk :(
Sav_1012
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what is it