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eyust707Best ResponseYou've already chosen the best response.0
well they are both just triangles minus the same little corner...
 one year ago

cwrw238Best ResponseYou've already chosen the best response.1
The whole figure is a square and the line bisects the right side of the square. this question was from a maths paper for 16 year old's. I would have struggled to do this at 16  probably would have given up.
 one year ago

eyust707Best ResponseYou've already chosen the best response.0
dw:1341591736170:dw p = (1*2)/2  A q= (2*2)/2  A Subtracting the same amount from both wont effect the ratio, so: p:q = 1/2
 one year ago

eyust707Best ResponseYou've already chosen the best response.0
*i think*** lol i havent taken geometry since 10th grade
 one year ago

eyust707Best ResponseYou've already chosen the best response.0
haha thats a cool one though!
 one year ago

eyust707Best ResponseYou've already chosen the best response.0
What do you think does my logic seem sound?
 one year ago

cwrw238Best ResponseYou've already chosen the best response.1
no  thats not the answer
 one year ago

eyust707Best ResponseYou've already chosen the best response.0
hmm maybe you can tjust take off the A
 one year ago

eyust707Best ResponseYou've already chosen the best response.0
but if we find that little A we are golden
 one year ago

eyust707Best ResponseYou've already chosen the best response.0
I could do it using trig but thats a pain and I know there's an easier way...
 one year ago

cwrw238Best ResponseYou've already chosen the best response.1
i did it differently using systems of equations there maybe an easier way though this is how i started
 one year ago

phiBest ResponseYou've already chosen the best response.1
dw:1341592415019:dw we can label the sides of the square 1 for easy calculation. similar triangles p and x, with x scaled by 1/2 means the area of x is 1/4 of p the rest of the areas are easy to find.
 one year ago

cwrw238Best ResponseYou've already chosen the best response.1
area x : area y = 1^2 : 2^2 = 1: 4 then i got 4 equations in x, y , p and q and splved  a bit messy !!
 one year ago

cwrw238Best ResponseYou've already chosen the best response.1
yea  i think thats a bit better way than mine
 one year ago

eyust707Best ResponseYou've already chosen the best response.0
haha phi isnt that just the same problem again... dw:1341592696668:dw
 one year ago

phiBest ResponseYou've already chosen the best response.1
the altitudes are also in ratio of 1/2 so p's alt is 1/3 and x's is 1/6 as they add to 1/2
 one year ago

phiBest ResponseYou've already chosen the best response.1
so find the area of p, area of q is (1/2)^2 + (1/2)*(1/2)^2 + area(x)
 one year ago

cwrw238Best ResponseYou've already chosen the best response.1
so q = 1/4 + 1/8 + area(x) = 3/8 + area(x)
 one year ago

phiBest ResponseYou've already chosen the best response.1
area(x)= (1/2)*(1/2)*(1/6)= 1/24 area(p)= (1/2)*1*(1/3)= 1/6
 one year ago

phiBest ResponseYou've already chosen the best response.1
so ratio of areas p/q = 2/5
 one year ago

cwrw238Best ResponseYou've already chosen the best response.1
i got 2: 5 area p = 1/6 area q = 3/8 + 1/24 = 10/24 = 5/12 p/q = 1/6 * 12/5 = 12/60 = 2/5  yea
 one year ago

cwrw238Best ResponseYou've already chosen the best response.1
 quite a searching question for 16 year old, i thought
 one year ago

phiBest ResponseYou've already chosen the best response.1
Back in the old days, maybe they worked harder at this stuff??
 one year ago
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