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cwrw238 Group TitleBest ResponseYou've already chosen the best response.1
dw:1341591452831:dw
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.0
well they are both just triangles minus the same little corner...
 2 years ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.1
The whole figure is a square and the line bisects the right side of the square. this question was from a maths paper for 16 year old's. I would have struggled to do this at 16  probably would have given up.
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.0
dw:1341591736170:dw p = (1*2)/2  A q= (2*2)/2  A Subtracting the same amount from both wont effect the ratio, so: p:q = 1/2
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.0
*i think*** lol i havent taken geometry since 10th grade
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.0
haha thats a cool one though!
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.0
What do you think does my logic seem sound?
 2 years ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.1
no  thats not the answer
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.0
hmm maybe you can tjust take off the A
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.0
but if we find that little A we are golden
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.0
I could do it using trig but thats a pain and I know there's an easier way...
 2 years ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.1
i did it differently using systems of equations there maybe an easier way though this is how i started
 2 years ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.1
dw:1341592406267:dw
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
dw:1341592415019:dw we can label the sides of the square 1 for easy calculation. similar triangles p and x, with x scaled by 1/2 means the area of x is 1/4 of p the rest of the areas are easy to find.
 2 years ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.1
area x : area y = 1^2 : 2^2 = 1: 4 then i got 4 equations in x, y , p and q and splved  a bit messy !!
 2 years ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.1
yea  i think thats a bit better way than mine
 2 years ago

eyust707 Group TitleBest ResponseYou've already chosen the best response.0
haha phi isnt that just the same problem again... dw:1341592696668:dw
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
the altitudes are also in ratio of 1/2 so p's alt is 1/3 and x's is 1/6 as they add to 1/2
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
so find the area of p, area of q is (1/2)^2 + (1/2)*(1/2)^2 + area(x)
 2 years ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.1
so q = 1/4 + 1/8 + area(x) = 3/8 + area(x)
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
area(x)= (1/2)*(1/2)*(1/6)= 1/24 area(p)= (1/2)*1*(1/3)= 1/6
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
so ratio of areas p/q = 2/5
 2 years ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.1
i got 2: 5 area p = 1/6 area q = 3/8 + 1/24 = 10/24 = 5/12 p/q = 1/6 * 12/5 = 12/60 = 2/5  yea
 2 years ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.1
 quite a searching question for 16 year old, i thought
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
Back in the old days, maybe they worked harder at this stuff??
 2 years ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.1
yea  good point!
 2 years ago
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