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alexawb

  • 3 years ago

How would I go about writing the equation of the line which passes through (2, –3) and is perpendicular to y = 4x + 7 in standard form ?

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  1. SmoothMath
    • 3 years ago
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    First, consider the slope of the line y=4x+7. What will be the slope of a line perpendicular to it?

  2. tapan2721
    • 3 years ago
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    slope of y = 4x + 7 is 4 implies slope of desired line is -1/4 (m1* m2 = -1) so the eqn will be y+3 = -1/4(x-2) 4y + 12= 2-x 4y = -x - 10 y = -1/4(x +10)

  3. tapan2721
    • 3 years ago
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    or y = -1/4x -5/2

  4. SmoothMath
    • 3 years ago
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    Tell her why at least, Tapan. If two lines are perpendicular, then their slopes will be the opposite reciprocal. Reciprocal means flip it, opposite means switch the sign.

  5. alexawb
    • 3 years ago
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    thanks you both so much. What about the equation of the line which passes through (2, 1) and is perpendicular to x = –2 ? it doesnt ask for a certain form though..

  6. tapan2721
    • 3 years ago
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    x = -2 has a slope equal to 90 degrees so d slope of perp line will be = 0 that is parallel to x- axis so eqn will be y=1

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