How would I go about writing the equation of the line which passes through (2, –3) and is perpendicular to y = 4x + 7 in standard form ?

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How would I go about writing the equation of the line which passes through (2, –3) and is perpendicular to y = 4x + 7 in standard form ?

Mathematics
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First, consider the slope of the line y=4x+7. What will be the slope of a line perpendicular to it?
slope of y = 4x + 7 is 4 implies slope of desired line is -1/4 (m1* m2 = -1) so the eqn will be y+3 = -1/4(x-2) 4y + 12= 2-x 4y = -x - 10 y = -1/4(x +10)
or y = -1/4x -5/2

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Tell her why at least, Tapan. If two lines are perpendicular, then their slopes will be the opposite reciprocal. Reciprocal means flip it, opposite means switch the sign.
thanks you both so much. What about the equation of the line which passes through (2, 1) and is perpendicular to x = –2 ? it doesnt ask for a certain form though..
x = -2 has a slope equal to 90 degrees so d slope of perp line will be = 0 that is parallel to x- axis so eqn will be y=1

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