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alexawb
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How would I go about writing the equation of the line which passes through (2, –3) and is perpendicular to y = 4x + 7 in standard form ?
 2 years ago
 2 years ago
alexawb Group Title
How would I go about writing the equation of the line which passes through (2, –3) and is perpendicular to y = 4x + 7 in standard form ?
 2 years ago
 2 years ago

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SmoothMath Group TitleBest ResponseYou've already chosen the best response.0
First, consider the slope of the line y=4x+7. What will be the slope of a line perpendicular to it?
 2 years ago

tapan2721 Group TitleBest ResponseYou've already chosen the best response.0
slope of y = 4x + 7 is 4 implies slope of desired line is 1/4 (m1* m2 = 1) so the eqn will be y+3 = 1/4(x2) 4y + 12= 2x 4y = x  10 y = 1/4(x +10)
 2 years ago

tapan2721 Group TitleBest ResponseYou've already chosen the best response.0
or y = 1/4x 5/2
 2 years ago

SmoothMath Group TitleBest ResponseYou've already chosen the best response.0
Tell her why at least, Tapan. If two lines are perpendicular, then their slopes will be the opposite reciprocal. Reciprocal means flip it, opposite means switch the sign.
 2 years ago

alexawb Group TitleBest ResponseYou've already chosen the best response.0
thanks you both so much. What about the equation of the line which passes through (2, 1) and is perpendicular to x = –2 ? it doesnt ask for a certain form though..
 2 years ago

tapan2721 Group TitleBest ResponseYou've already chosen the best response.0
x = 2 has a slope equal to 90 degrees so d slope of perp line will be = 0 that is parallel to x axis so eqn will be y=1
 2 years ago
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