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hooverst

  • 2 years ago

Is there anyone who can help me with Calculus

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  1. tapan2721
    • 2 years ago
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    yup...go ahead

  2. zzr0ck3r
    • 2 years ago
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    im sure it depends?

  3. hooverst
    • 2 years ago
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    zzr0ck3r: depends on what?

  4. nbouscal
    • 2 years ago
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    Depends on the question. Please ask specific questions, anyone who can help you will surely do so.

  5. zzr0ck3r
    • 2 years ago
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    there is a calculus question that no one in hhere can do:) so it depends on what you need for help.

  6. hooverst
    • 2 years ago
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    find the equation of the secant line that passes through the graph of f(x)=x^3 at x=-3 and x=4 .

  7. nbouscal
    • 2 years ago
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    Unless I'm mistaken, calculus methods aren't necessary for that. Simply find the coordinates of f(x)=x^3 at x=-3 and x=4, and then find the line through the two points.

  8. hba
    • 2 years ago
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    where is the calculus

  9. hooverst
    • 2 years ago
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    ok thanks

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