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jk_16
Solve the limit: limit as h goes to infinity of [(1/h)] / [1+(1/h)] I know its one, but I can get it as 0/0 how can I proof its one? thanks
limit as h goes to infinity of [(1/h)] / [1+(1/h)] = limit as h goes to infinity of [(1/h)] / [(h+1)/h)] = = limit as h goes to infinity of [(1/ [(h+1)] = 0
crapp wrong one..its: Solve the limit: limit as h goes to infinity of [(1/h)] / [nl 1+(1/h)]
i think this will just be zero